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C. Harmony Analysis

time limit per test

3 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputThe semester is already ending, so Danil made an effort and decided to visit a lesson on harmony analysis to know how does the professor look like, at least. Danil was very bored on this lesson until the teacher gave the group a simple task: find 4 vectors in 4-dimensional space, such that every coordinate of every vector is 1 or - 1 and any two vectors are orthogonal. Just as a reminder, two vectors in *n*-dimensional space are considered to be orthogonal if and only if their scalar product is equal to zero, that is:

Danil quickly managed to come up with the solution for this problem and the teacher noticed that the problem can be solved in a more general case for 2^{k} vectors in 2^{k}-dimensinoal space. When Danil came home, he quickly came up with the solution for this problem. Can you cope with it?

Input

The only line of the input contains a single integer *k* (0 ≤ *k* ≤ 9).

Output

Print 2^{k} lines consisting of 2^{k} characters each. The *j*-th character of the *i*-th line must be equal to ' * ' if the *j*-th coordinate of the *i*-th vector is equal to - 1, and must be equal to ' + ' if it's equal to + 1. It's guaranteed that the answer always exists.

If there are many correct answers, print any.

Examples

Input

2

Output

++**

+*+*

++++

+**+

Note

Consider all scalar products in example:

- Vectors 1 and 2: ( + 1)·( + 1) + ( + 1)·( - 1) + ( - 1)·( + 1) + ( - 1)·( - 1) = 0
- Vectors 1 and 3: ( + 1)·( + 1) + ( + 1)·( + 1) + ( - 1)·( + 1) + ( - 1)·( + 1) = 0
- Vectors 1 and 4: ( + 1)·( + 1) + ( + 1)·( - 1) + ( - 1)·( - 1) + ( - 1)·( + 1) = 0
- Vectors 2 and 3: ( + 1)·( + 1) + ( - 1)·( + 1) + ( + 1)·( + 1) + ( - 1)·( + 1) = 0
- Vectors 2 and 4: ( + 1)·( + 1) + ( - 1)·( - 1) + ( + 1)·( - 1) + ( - 1)·( + 1) = 0
- Vectors 3 and 4: ( + 1)·( + 1) + ( + 1)·( - 1) + ( + 1)·( - 1) + ( + 1)·( + 1) = 0

Codeforces (c) Copyright 2010-2019 Mike Mirzayanov

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