I tried accessing clist.by but it gives a a 504 error. Is this the same for others? How long will the site be down for?

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Problem Statement: this Is there a way to prove that if we are not able to connect the vertices to 1 in the greedy order that has been suggested, then there exists no other answer?

Thanks.

This video(copied with time stamp) presents an approach to solving problem 1665C and I understood the broad approach but I am not able to understand that if we have the sum of left over vertices after considering infection is greater than the number of injection operations remaining we directly say that x is not possible, but shouldn't we also consider the fact that even if we have less injections left, they would all still spread in parallel at any given time?

For example lets say that x = 3 and the sum of count values is 4. And this value comes from two sets comprising of two sibling nodes. Then it is possible to infect all of them in 3 seconds, because once we infect one of them the infection spreads to the sibling. So this is why I have this doubt, maybe I might have misunderstood something in which case I would really appreciate any help

Hello, I wanted to know why the this submission was giving TLE. Thanks :)

The problem in question is Hamiltonian wall and I wrote a solution to this that works, but I suspect that it is the wrong solution. My solution is this. The reason I suspect that my solution is incorrect is because, if in the DFS function I change the order of the two loops, I get the wrong answer(when that should not be happening). I would really appreciate if anybody could point out what is wrong with DFS function.

Thanks, if you need any clarification regarding some of the terms in my template or regarding my approach, feel free to comment down below EDIT: I removed the lengthy template

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