Hi, I am having problem with solving this task from my math homework. If number p is prime and p^2+8 is also prime. Prove that p^3+4 is also prime number.
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3880 |
2 | jiangly | 3669 |
3 | ecnerwala | 3654 |
4 | Benq | 3627 |
5 | orzdevinwang | 3612 |
6 | Geothermal | 3569 |
6 | cnnfls_csy | 3569 |
8 | jqdai0815 | 3532 |
9 | Radewoosh | 3522 |
10 | gyh20 | 3447 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | awoo | 161 |
2 | maomao90 | 160 |
3 | adamant | 156 |
4 | maroonrk | 153 |
5 | -is-this-fft- | 148 |
5 | atcoder_official | 148 |
5 | SecondThread | 148 |
8 | Petr | 147 |
9 | nor | 144 |
9 | TheScrasse | 144 |
Hi, I am having problem with solving this task from my math homework. If number p is prime and p^2+8 is also prime. Prove that p^3+4 is also prime number.
Название |
---|
Suppose that p ≠ 3. Then
thus p2 + 8 is not prime and we were wrong in our assumption. Then p = 3 and p3 + 4 = 31 which is obviously prime.
How to prove that p2 = 1 mod 3?
Fermat's little theorem. If p is prime, then
This is a special case of Euler's theorem, which is formulated like this for coprime a, m:
![](/predownloaded/28/6b/286b8c4b2dbac8793bc65bcf7d33660b038fc563.png)