Wish you good luck and have a nice time! (๑^ω^๑)

And tell you a secret: I will choose two participants randomly after the contest and give them some gifts made by myself!
-- AquaMoon

Wow! Thanks for your support! (●'◡'●)

As a tester, I think it will be the best round of year $$$2022$$$. I would also prefer to participate.

UPD: sorry for such an issue.

Cute Little09! o(〃'▽'〃)o

Yes! Btw orz ChthollyNotaSeniorious (>▽<)

Maybe the title influences on the tasks scarcely ✧⁺(๑•ω•๑)⁺✧

Wish you IM (●'◡'●)

Wish you good luck and enjoy yourself! (๑^ω^๑)

Sorry, not our round (●'◡'●) please click here : https://codeforces.com/blog/entry/110056

Sorry, not our round (●'◡'●) please click here : https://codeforces.com/blog/entry/110056

My man got time machine

Technically yes. There exists a random order of operations that happens to be the correct order of operations. But random is most likely to be as successful as BOGO sort. (Which means that it will probably not work)

In this case, I think most random algorithms (I can think of) works poorly when N is small. Also this problem has mutitasks in a test case, so the accuracy for small N may need to be larger than 1-10^9... But algos based on random still have chances to AC this problem

Wish you good luck and happy everyday!!! Don't be upset !!! I believe you will have a good time (๑^ω^๑)

Thanks for your support! Wish you good luck! o(〃'▽'〃)o

Missed it tho. :[

Mejiamejia is said to have proposed 3 div1F, he is currently hibernating because it is winter, please come back in april at deltix lab round 5

There are many so called setters that just want to farm author or something ( not saying mejiamejia is one of them, because I don't know ), there are many rounds in which people appear as writers even tho they didn't set a single problem.

Look at this, a D2D that has 6 chinese authors, which I think it's cap.

orz DataStructures (>▽<)

Thanks for your support! (●'◡'●)

The moon shines, thank the moon.

Yes

Maybe it is a good opportunity to improve your comprehensive abilities in coding! ✧⁺(๑•ω•๑)⁺✧

Hoping all contests to be exciting.

Thanks! It's my favourite ~ o(〃'▽'〃)o

What's so bad about Combinatorics!? Its my fav!

what's the meaning of FFT?

(〃•ω‹〃)

Be happier bro, the round written by mejiamejia always turns into a sorry round. I wish you a pleasant journey!

Me too.

Sometimes even if your English is good you still cannot understand the problem bcoz they twist the problem . but wishing best for you.

Don't worry, tomorrow's World Cup final will be more exciting. Enjoy this round!

all the best brother

Updated. o(〃'▽'〃)o

The score distribution of combined rounds are similar to Div.2 (at least in my experience)

As an all-getter of 1500, the true difficult thing is when I start hacking. So sad.

This round is rated for every user.

My solution is also wrong :(

And also if only one notice that he can hack most of his room which is unfair for all competitors

True

True

did you check if the column's value of row with maximum ones is 1 and the minimum's is 0? because if you just check if they have different value, then you might just adding more 1 to the maximum and removing from the minimum

No hacks for D apparently. It will be interesting if there will be many FSTs on D as well.

Nevermind. Here is the logic of D:

There will always be a spot for which you have 1-0 if you still have a different count of ones, because you have target — 1 and target + 1 count of 1s. That is all. Therefore it doesn't matter what order you choose to do the place swaps.

It's very sad to see participants hacked a not hard problem through the same data and gain high marks.

same

that hacker must be smart though, so you couldn't go and hacked other people that he would then hacked

.

As if solving A-D wasn't painful enough already. Not a nice round. E was gorgeous, other problems I won't comment.

Why shouldn't there be a problem once in a while with some weak pre-tests? It's an opportunity for us all to hunt down bugs in others' code.

There is no guarantee that pre-tests are going to verify your solution to the problem. You're supposed to write a correct answer without depending on pre-tests.

There are very few opportunities for hacks on Codeforces rounds when the pre-tests are extensive and, in fact, most rounds have almost no points for successful hacks.

Let's mourn for Mr_Eight's $$$\operatorname{L\color{red}{GM}}$$$ /(ㄒoㄒ)/~~.

What happened: Mr_Eight is a handsome and powerful CPer in China. He became $$$\operatorname{L\color{red}{GM}}$$$ last month, gaining $$$\operatorname{L\color{red}{GM}}$$$ for his all 3 alts. However, A sweet fruit is short-lived. He lost his $$$\operatorname{L\color{red}{GM}}$$$, just because he attempts to solve G and doesn't notice the hack in B. He find all hackable solutions hacked before he can find out how to hack, while over $$$\frac{1}{3}$$$ of the guys ranking above him is above him because of hacking.

I feel very sorry for him. Had he conquered G or even revised his B and hacked before qtpk(he hacked 14 including Mr_Eight), he'd not lost $$$\operatorname{L\color{red}{GM}}$$$, even gaining some rating instead (>_<).

But he still have 2 $$$\operatorname{L\color{red}{GM}}$$$ alts. We can still orz to him(>▽<).

F1 is is brute force . You can implement it with map in O(nlog^2n).

Although I didn't manage to do it in time I solved it with a treap. I relied on the fact that $$$x \leq 2 * 10^5$$$ and made a rope to easily deal with a second type of operation.

i am waiting to be hacked!!

include<bits/stdc++.h>

using namespace std;

define int long long int

int32_t main(){ int tc; cin>>tc; while (tc--) {

int n;
    cin>>n;
    string s;
    cin>>s;
    int curr = 1;
    int count = 0;
    char now = '.';
    for(int i = 0; i < s.size(); i++){
        if(s[i] != now){
            now = s[i];
            count += curr;
            curr = 1;
        }else{
            curr += 1;
        }
        cout<<count<<" ";
    }cout<<endl;
}

return 0;

}

What is the answer Yes or no

Happened in yesterday's contest too where D got leaked

A recurring theme here at codeforces :(. We've seen this happening too many times...

I agree that cheating is a problem and that harsher punishment to it is required, but saying that a problem has 5k AC just because of cheating is insane. I find it incredibly farfetched to believe that even 1k people ACed C by cheating.

I think you worry too much about ranking :) You should mostly judge the round for task quality, i.e. if it was fun to solving them.

p.s. I do not say that I like/dislake this round and its tasks.

Hacking is part of Codeforces. We need more rounds where the pre-tests are not a crutch for all the participants and some incorrect solutions can get hacked.

There are more, a lot of people (in my room) dodged this one with if (K > m) { cout << "NO"; } but still had incorrect solutions.