How can we solve spoj problem INCSEQ using segment tree?
Here is the link to the problem
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3690 |
2 | jiangly | 3647 |
3 | Benq | 3581 |
4 | orzdevinwang | 3570 |
5 | Geothermal | 3569 |
5 | cnnfls_csy | 3569 |
7 | Radewoosh | 3509 |
8 | ecnerwala | 3486 |
9 | jqdai0815 | 3474 |
10 | gyh20 | 3447 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | maomao90 | 172 |
2 | adamant | 164 |
3 | awoo | 163 |
4 | TheScrasse | 160 |
5 | nor | 157 |
6 | maroonrk | 155 |
7 | -is-this-fft- | 152 |
8 | Petr | 146 |
9 | orz | 145 |
9 | pajenegod | 145 |
How can we solve spoj problem INCSEQ using segment tree?
Here is the link to the problem
Название |
---|
I think, that you can solve this task in such way :
You will use K segment trees.
1. Sort all elements of given array in non-decreasing order.
About sort : if elements are equal — the minimal element will be element which has the rightmost position.
2. You should update every segment tree in such way :
3. Le'ts add the value of sum in the current segment tree in position myElementPosition.
My AC code here
If I want to find distinct increasing subsequence as in this question http://www.spoj.com/problems/INCDSEQ/
what modification I need to make in the above code?
Another ways to solve the problem:
Can you please explain how BIT is working for this problem? Also , why we need to increment a[i] during scanning the input
Increment is because BIT is 1-based structure. Bit-based solution is simply in k turns calculate on each turn number of sequences of length i ending in pos.