Блог пользователя csacademy

Автор csacademy, 7 лет назад, По-английски

Hello, Codeforces!

We're going to host a new contest at csacademy.com. Round #67 will take place on Wednesday, 31/January/2017 15:35 (UTC). This contest will be a Div1 + Div2, with 7 tasks of varying difficulty that need to be solved in 2 hours.

We are glad to have khadaev as a problem setter again.

Facebook event

Recently, Facebook has reintroduced the possibility of recurring events. If you choose "Interested" here, you will be notified before each round we organise from now on.

Contest format:

  • You will have to solve 7 tasks in 2 hours.
  • There will be full feedback throughout the entire contest.
  • Tasks will not have partial scoring, so you need to pass all test cases for a solution to count (ACM-ICPC-style).
  • Tasks will have dynamic scores. According to the number of users that solve a problem the score will vary between 100 and 1000.
  • Besides the score, each user will also get a penalty that is going to be used as a tie breaker.

Prizes

We're going to award the following prizes:

  1. First place: 100$
  2. Second place: 50$

About the penalty system:

  • Computed using the following formula: the minute of the last accepted solution + the penalty for each solved task. The penalty for a solved task is equal to log2 (no_of_submissions) * 5.
  • Solutions that don't compile or don't pass the example test cases are ignored.
  • Once you solve a task you can still resubmit. All the following solutions will be ignored for both the score and the penalty.

If you find any bugs please email us at [email protected]

Don't forget to like us on Facebook, VK and follow us on Twitter.

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7 лет назад, # |
  Проголосовать: нравится +20 Проголосовать: не нравится

Could you delay the round by 10-15 mins ?
It would allow people to participate in both CF #460 and CSA #67.

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7 лет назад, # |
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Wow, solution to last task is really magical...

I also really liked problem E. My first thoughts were something like "oh no, this is probably yet another problem about this xor convolution with probably some divide and conquer", but then it turned out it is really cute :)

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    7 лет назад, # ^ |
      Проголосовать: нравится 0 Проголосовать: не нравится

    Actually, my solution is sqrt-decomposition + something similar to 'this xor convolution' :)

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      7 лет назад, # ^ |
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      E appeared with the same approach in International Zhautykov Olympiad 2017

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    7 лет назад, # ^ |
      Проголосовать: нравится +6 Проголосовать: не нравится

    And luckily for me, problem E can be solved with O(N·2M) complexity :-)

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    7 лет назад, # ^ |
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    My over-complicated solution: Divide array into blocks of size K. For a chunk update, we use dp on bits with complexity O(n+2^m*m*m) and query in O(K+m) by iterating on elements in same block. On optimally choosing k, this gives same complexity as editorial but with larger constant. Code