suppose u have to find a % b , i see many red coders solution instead of using directly a%b they do like ..
if (a >=mod) a-=mod ??
why so ?
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suppose u have to find a % b , i see many red coders solution instead of using directly a%b they do like ..
if (a >=mod) a-=mod ??
why so ?
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Its faster(if you do addition like 1e6(1,000,000) or more times in a program, writing an addition function using this if instead of % will save a lot of time),but this can be used only for addition and a similar if for subtraction. It can not be used for multiplication.
The plausible reason should be that the execution time of the statement
if(a >= b) a -= b;
is more likely to be less than the execution time of the statementa %= b;
when it is guaranteed that the expressiona < 2*b
is true. You may write a short C++ program to compare the average execution time of both statements so as to confirm or refute this hypothesis.Yes , i checked in c++14 , its 3.6 times faster than % .. thanks nikolapesic2802 , CodingKnight
With pleasure. Thanks for sharing the result of the experiment.
because
1000 ms
8700 ms