ismail's blog

By ismail, history, 12 months ago, In English

Problem Details:

Contest : Codeforces Round #589 (Div. 2)

Problem : 1228B - Заполнение таблицы

Solution : Submission

Solution Explanation:

Create a matrix a[r+2][c+2] to hold cell information (2 extra index for 1 based indexing + no need to check overflow)

Cell information:

-1 = Free (can be White or Black)

0 = Reserved (Must be empty and immutable)

1 = Occupied (Black cell)

[ To make r and c valid, reserved cell never be changed ]

Logic:

  1. Initialize all cell as free (-1). memset(a, -1, sizeof(a[0][0]) * (r + 2) * (c + 2));

  2. Take input for each row (1 to h) as "d" and do the following:

    • Make cell d+1 reserved :=> If d==0, then 1st cell (for 1 base indexing, cell d+1=1 is the 1st cell) must be reserved (0) otherwise cell d+1 reserved because if d+1 cell changed to black then r will be invalid.
    • Then make all (1 to d) cell occupied (1)
  3. Take input for each col (1 to w) as "d" and do the following:(Same as logic 2, just extra need to checkout reserved cell is occupied or not before making new cell reserved or occupied)

    • Check required reserved cell is occupied or not. If occupied then it's impossible to make a grid to satisfy such r, c values, so return 0 with "0" output.
    • Make cell d+1 reserved.
    • Then make all (1 to d) cell occupied (1) BUT before made occupied check it previously reserved or not. If reserved then return 0 with "0" output.
  4. Count how many free (-1) cell do you have for combinations. If free cell is zero then ans = 1(initialized) otherwise ans = 2^free_cell.

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Solution / Code:

Happy coding

 
 
 
 
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12 months ago, # |
  Vote: I like it +3 Vote: I do not like it

Can you make a similar for the rest

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2 months ago, # |
  Vote: I like it 0 Vote: I do not like it

Thanks for the editorial it has been of great help understanding the problem.