salt_n_ice's blog

By salt_n_ice, history, 6 weeks ago, In English

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Code
    ll n, c;
    cin>>n>>c;
    vector<pair<ll, ll> > v;
    for(int i=0; i<n; ++i)
    {
        ll a,b,p;
        cin>>a>>b>>p;
        v.push_back({a, p});
        v.push_back({b+1, -p});
    }
    sort(v.begin(), v.end());
    ll ans = 0;
    ll accum = 0;
    for(int i=0; i<2*n; ++i)
    {
        ll a = v[i].first, p = v[i].second;
        accum += p;
        if(i+1<2*n)
        {
            ans += min(accum*(v[i+1].first-a), c*(v[i+1].first-a));
        }
    }
    cout<<ans<<endl;

After submitting this solution, there is a single test case out of 28 which is giving WA. And I don't see what's wrong with this solution. I don't think the problem is with constraints either.

 
 
 
 
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6 weeks ago, # |
  Vote: I like it +1 Vote: I do not like it

You could find the test cases for all Atcoder problems here. Maybe that will help.

  • »
    »
    6 weeks ago, # ^ |
    Rev. 2   Vote: I like it 0 Vote: I do not like it

    Thanks.
    For someone having a similar problem, The reason is probably overflowing.
    ans += min(accum*(v[i+1].first-a), c*(v[i+1].first-a)); At this step, accum could be up to 10^14 so:
    ans += (v[i+1].first-a) * min(accum, c); will be good.