Hey; Here here is the problem.I write a solution , but i could not found where my bug is :(
~~~~~ ~~~~~ Could you guys find the bug please ? Edit:Ok i got it.
# | User | Rating |
---|---|---|
1 | tourist | 3851 |
2 | jiangly | 3634 |
3 | Um_nik | 3539 |
4 | slime | 3498 |
5 | ksun48 | 3493 |
6 | djq_cpp | 3486 |
7 | maroonrk | 3471 |
8 | MiracleFaFa | 3466 |
9 | Radewoosh | 3442 |
10 | Petr | 3426 |
# | User | Contrib. |
---|---|---|
1 | -is-this-fft- | 183 |
2 | awoo | 181 |
3 | YouKn0wWho | 177 |
4 | Um_nik | 175 |
5 | dario2994 | 172 |
6 | Monogon | 170 |
6 | adamant | 170 |
8 | maroonrk | 169 |
9 | errorgorn | 166 |
10 | antontrygubO_o | 165 |
Hey; Here here is the problem.I write a solution , but i could not found where my bug is :(
~~~~~ ~~~~~ Could you guys find the bug please ? Edit:Ok i got it.
You will read the number N (1<=N<=100) than i will give you N*N numbers. I want you to find the rectangle which is has the most sum and print its sum. Input: 5 1 2 3 4 5 1 -5 -20 -40 4 -8 -7 5 6 2 -5 2 -4 -8 9 1 -5 -8 -5 2 Output: 22 Is this problem has a solution better than o(n^4) ?
In this submisson: 2431151 In that line: "if(hour[i]==hour[i-1]&&min[i]==min[i-1]){"
In the beginning, i=0 so that hour[i-1] means hour[-1].Can someone please explain how can this pass the pretests?
Name |
---|