Package for this problem was not updated by the problem writer or Codeforces administration after we’ve upgraded the judging servers. To adjust the time limit constraint, solution execution time will be multiplied by 2. For example, if your solution works for 400 ms on judging servers, then value 800 ms will be displayed and used to determine the verdict.

Virtual contest is a way to take part in past contest, as close as possible to participation on time. It is supported only ICPC mode for virtual contests.
If you've seen these problems, a virtual contest is not for you - solve these problems in the archive.
If you just want to solve some problem from a contest, a virtual contest is not for you - solve this problem in the archive.
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A. Next Round

time limit per test

3 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard output"Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.

A total of *n* participants took part in the contest (*n* ≥ *k*), and you already know their scores. Calculate how many participants will advance to the next round.

Input

The first line of the input contains two integers *n* and *k* (1 ≤ *k* ≤ *n* ≤ 50) separated by a single space.

The second line contains *n* space-separated integers *a*_{1}, *a*_{2}, ..., *a*_{n} (0 ≤ *a*_{i} ≤ 100), where *a*_{i} is the score earned by the participant who got the *i*-th place. The given sequence is non-increasing (that is, for all *i* from 1 to *n* - 1 the following condition is fulfilled: *a*_{i} ≥ *a*_{i + 1}).

Output

Output the number of participants who advance to the next round.

Examples

Input

8 5

10 9 8 7 7 7 5 5

Output

6

Input

4 2

0 0 0 0

Output

0

Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.

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