void solve(int N,int P){
if(N==0)
{
cout<<"yes\n";
return;
}
if(N-2>=0){
solve(N-2,P);
}
if(N-3>=0){
solve(N-3,P);
}
}
It's showing runtime error for N = 200000(Ignore P) . Why ??
void solve(int N,int P){
if(N==0)
{
cout<<"yes\n";
return;
}
if(N-2>=0){
solve(N-2,P);
}
if(N-3>=0){
solve(N-3,P);
}
}
It's showing runtime error for N = 200000(Ignore P) . Why ??
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Even if you write simple fibonacci recursive function, you will get RE at big tests. It is because program did a lot of recursive calls.
To know more and unterstand how to avoid it, learn basics of DP (dynamic programming).
wont work for n>=3 coz it will end up at n=1(which doesnt have any return statement), also there will be plenty of yes printed for every number and i dont think you would want that...