Can anybody please explain me the following part of this Solution:- int t = H[h][l].second ^ H[h][r].second; bool ok = t — (t & -t); if(!ok) printf("Yes\n"); else printf("No\n");
Problem 570-D
Can anybody please explain me the following part of this Solution:- int t = H[h][l].second ^ H[h][r].second; bool ok = t — (t & -t); if(!ok) printf("Yes\n"); else printf("No\n");
Rev. | Язык | Кто | Когда | Δ | Комментарий | |
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en1 | Abhibansal53 | 2015-08-19 14:23:46 | 272 | Initial revision (published) |