atcoder_official's blog

By atcoder_official, history, 8 days ago, In English

We will hold AtCoder Beginner Contest 367.

We are looking forward to your participation!

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7 days ago, # |
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In the codeforces handle section on profile page anyone can anyone's handle so what's the use of it?

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    7 days ago, # ^ |
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    It is based on the trust system which is relatively common in Japan. For example, you have snacks that you can take and then put in the box the amount of money equal to their price. Nobody is watching to see whether you will put in the money or not, but everyone pays. Of course, there is no way this would work in western countries.

    For real though, what do you gain by putting someone else's handle?

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7 days ago, # |
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I hope I can solve ABCD, and I hope everyone can get a good score.

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7 days ago, # |
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Problem E: https://cp-algorithms.com/algebra/binary-exp.html#applying-a-permutation-k-times

Problem F: https://codeforces.com/blog/entry/85900?#comment-736594

atcoder_official I completely understand if there is a shortage of problems for ABCs, but what is the point of putting such well known problems? I would rather have an ABC maybe two times a month but with better problems.

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    7 days ago, # ^ |
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    ABCs nowadays are dogshit. First few probelms are usually ways trivial and most had appeared somewhere before, and the last one is usually too hard, only some chinese or IGM+ solve it LOL

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7 days ago, # |
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HOW CAN SOMEONE WRITE SUCH WELL COMMENTED SOLUTION for PROBLEM A, under 40 seconds ( Provided, you have to read the question as well ) .

https://atcoder.jp/contests/abc367/submissions/56773722

UNLESS of course, GPT.

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    7 days ago, # ^ |
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    I've had a look at his submissions, and it turns out that only A and B are coded in this style, as his submissions on problems C, D, E and F have completely different style and template.

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7 days ago, # |
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How can this submition1 TLE in promblem E? About 30 minutes later i just add one line assert submition2 and pass. This bothers me very much in the contest.

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    7 days ago, # ^ |
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    Can you explain your approach for the problem E ?

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      7 days ago, # ^ |
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      This is the basic binary jumping problem. Usaco guide will help you, and problem E is like this CSES problem. In brief of E, just make the binary jumping table for X, and jumping k times for each start position i.

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    7 days ago, # ^ |
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    Also the statement of problem D is very comfused, "The minimum number of steps required to walk clockwise from rest area s to rest area t". What minimum?

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      7 days ago, # ^ |
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      If it didn't specify "minimum" then you could choose to walk all the way around the lake from $$$s$$$ back to $$$s$$$ any number of times, then continue to $$$t$$$, resulting in (potentially) different numbers of steps modulo $$$M$$$ for the same pair $$$(s, t)$$$.

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        7 days ago, # ^ |
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        Can you help me explain why my approach for D is wrong

        My submission

        My approach : First I find all subarrays whose sum is multiple of M Secondly , I find all the subarrays such that their sum%mod equals entire arrays sum .

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    7 days ago, # ^ |
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    I don't know why submission1 has TLE and submission2 doesn't have TLE.(some optimization?) But it is slow to access memory randomly. By accessing memory simultaneously for i=1..n, it becomes faster because of caching. https://atcoder.jp/contests/abc367/submissions/56834042

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    7 days ago, # ^ |
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    diobrando97 I guess the assert changed the compiler optimization behavior, if you removed the unroll-loops optimization your code will pass, so the assert kind of prevents this optimization or changes its behavior.
    Just comment this out pragma GCC optimize("O3,unroll-loops")

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      7 days ago, # ^ |
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      No assert and comment " #pragma GCC optimize("O3,unroll-loops")" =>TLE * 12

      No assert and comment " #pragma GCC optimize("O3,unroll-loops") #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")" => TLE * 4

      With assert and comment " #pragma GCC optimize("O3,unroll-loops") #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")" => Pass with 1978s

      Magic

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7 days ago, # |
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can someone tell why this code fails for D? I translated the problem as, count of subarrays have sum % m == 0 and size of subarray >= 2. for that im using prefix sums. for an array a $$$ a_1, a_2, ..., a_n $$$, I create prefix sums with the array $$$ a_1, a_2, ..., a_n, a_1, a_2, ... a_n-1 $$$ . then I just count mods and calculate answer.

Submission

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    7 days ago, # ^ |
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    Size of subarray can be taken to be 1 as well if you think. Main constraint is that the size of subarray can't be taken as n.

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      7 days ago, # ^ |
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      I now understand that it can be taken as 1 but I think my code already deals with it. no clue what else is going wrong. ig i'll have to wait for testcases to come out on dropbox

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    6 days ago, # ^ |
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    I modified your submission. Now it can pass.

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      6 days ago, # ^ |
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      can you explain?

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        6 days ago, # ^ |
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        Consider this test case;

        Spoiler

        There are only 2 rest areas. The answer is 2 (From 1 to 2 and from 2 to 1). Your solution outputs 4. It is over-counting.

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          6 days ago, # ^ |
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          so if talk in terms of explanation, we have to adjust the sliding window before moving onto the ith index?

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7 days ago, # |
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Problem E was basically this

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7 days ago, # |
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how to solve d and f?

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6 days ago, # |
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In problem G, if we don't care about the size of the subsequence being a multiple of M then we can use xor basis to find the basis size let's call it b.

Then the answer is 2^(n-b) * sum(representable value ^k)

However I hit a road bump when considering subsequence size, did any one solve it based on this approach?

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6 days ago, # |
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Can Someone explain Problem F, I understood it was hashing but need some reference for it.