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Chef_Ka_Baap's blog

By Chef_Ka_Baap, history, 3 years ago, In English

ceil((double)x/n); x <= 10^12 and n <10^6; can anyone provide a test case or something I got hacked many times but was unable to find a mistake

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3 years ago, # |
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I can give you a reason why it can be wrong: because of how doubles are stored (IEEE 754), they might not be accurate, and that can lead to inaccurate result

if you want ceil, then use (x + n - 1) / n

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    3 years ago, # ^ |
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    is there any test case to show this i am unable to find one

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      3 years ago, # ^ |
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      it fails for bigger number like if you try to do 100000000000000001/100000000000000000 it will give you 1 directly but ceil of this should be 2

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        3 years ago, # ^ |
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        but test case allow 10^12 for x and 10^6 for n

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          3 years ago, # ^ |
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          You can try stress-testing. I believe ceil() will cause precision error by nature, regardless of the constraints.

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    3 years ago, # ^ |
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    but if we give by this method ie (x+n-1)/n then wont it lead to overflows due to addition?

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      3 years ago, # ^ |
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      yes

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      3 years ago, # ^ |
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      I don't think any problem setter would be that evil.

      Also, if you are afraid of overflow, you can try x / n + (x % n != 0), although it requires more divisions, which is slower and uglier (but I guess it's easier to understand).

      And, __int128 is also an option as well, you can have a look at it.