inbarin's blog

When the problem (G) is sus — round 719 div 3
By inbarin, history, 3 years ago, In English

did anyone else notice the LONG evaluation time or am I a noob? insert inspirational quote here to make this post seem reasonable

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3 years ago, # |
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What was your logic for solving it ?

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    3 years ago, # ^ |
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    since the cost is the sum we can think of portals as a different edge to the "portal dimension". I didn't realize this until just now, so I had the following idea: there are two options. A — just walk the entire way or B — walk from the start to a portal, and then from a portal to the end. calculating A is possible with a graph search (but block visited nodes) calculating B is possible with 2 more searches. (it is actually 2 parts — from start to portal + from portal to end.

    then the minimum cost of the 2 options is the true cost. note: time needed = cost

    I am bad at explaining so my best attempt is to claim that you can prove this answer correct,

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3 years ago, # |
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Something similar was discussed in this blog. The last tests run very slowly.

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3 years ago, # |
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sus :flushed:

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