| # | User | Rating |
|---|---|---|
| 1 | tourist | 3880 |
| 2 | jiangly | 3669 |
| 3 | ecnerwala | 3654 |
| 4 | Benq | 3627 |
| 5 | orzdevinwang | 3612 |
| 6 | Geothermal | 3569 |
| 6 | cnnfls_csy | 3569 |
| 8 | jqdai0815 | 3532 |
| 9 | Radewoosh | 3522 |
| 10 | gyh20 | 3447 |
| # | User | Contrib. |
|---|---|---|
| 1 | awoo | 161 |
| 2 | maomao90 | 160 |
| 3 | adamant | 156 |
| 4 | maroonrk | 153 |
| 5 | -is-this-fft- | 148 |
| 5 | atcoder_official | 148 |
| 5 | SecondThread | 148 |
| 8 | Petr | 147 |
| 9 | nor | 144 |
| 9 | TheScrasse | 144 |
This formula:$$$A(n, m) = \sum_{i = 0}^{m} (-1)^i {n + 1 \choose i}(m + 1 - i)^n$$$
Eulerian number is the number of permutations of the numbers 1 to n in which exactly m elements are greater than the previous element, or exactly m elements satisfy P[i] > i(assume the permutation is P).
Updated: Here
