How my friends submission 80262789 for this problem 913A - Возведение в степень по модулю is accepted? Here 1 ≤ n ≤ 10^8 and he used pow() function for the value of 2^n.
Overflow But Accepted !
How my friends submission 80262789 for this problem 913A - Возведение в степень по модулю is accepted? Here 1 ≤ n ≤ 10^8 and he used pow() function for the value of 2^n.