Codeforces Round #333 — editorial

Правка en6, от Xellos, 2015-11-24 22:23:59

Hints:

div2A: Try conversions between bases.

div2B: Solve a simpler version of the problem where Ai + 1 ≠ Ai for all i.

div1A: What are the shortest paths of the vehicles? what's the shorter of those paths?

div1B: Forget about the ceiling function. Draw points (i, A[i]) and lines between them — what's the Lipschitz constant geometrically?

div1C: Some dynamic programming. Definitely not for the exp. score of one person — look at fixed scores instead.

div1D: Compute dif(v) in O(N) (without hashing) and then solve the problem in O(N2). Read my editorial of TREEPATH from Codechef.

div1E: Can you solve the problem without events of type 1 or 2? Also, how about solving it offline — as queries on subsets.

What, you thought I'd post solutions? Nope. Read the hints, maybe they'll help you. The solutions will appear here gradually.

Div. 2 A: The Two Routes


It's easy to compare two numbers if the same base belong to both. And our numbers can be converted to a common base — just use the formulas

A straightforward implementation takes O(N + M) time and memory. Watch out, you need 64-bit integers! And don't use pow — iterating is better.

Div. 2 C / Div. 1 A: The Two Routes


The condition that the train and bus can't meet at one vertex except the final one is just trolling. If there's a railway , then the train can take it and wait in town N. If there's no such railway, then there's a road , the bus can take it and wait in N instead. There's nothing forbidding this :D.

The route of one vehicle is clear. How about the other one? Well, it can move as it wants, so the answer is the length of its shortest path from 1 to N... or  - 1 if no such path exists. It can be found by BFS in time O(N + M) = O(N2).

In order to avoid casework, we can just compute the answer as the maximum of the train's and the bus's shortest distance from 1 to N. That way, we compute ; since the answer is  ≥ 1, it works well.

In summary, time and memory complexity: O(N2).

Bonus: Assume that there are M1 roads and M2 railways given on the input, all of them pairwise distinct.

Bonus 2: Additionally, assume that the edges are weighted. The speed of both vehicles is still the same — traversing an edge of length l takes l hours.

Теги codeforces, round, 333, editorial, pictures!

История

 
 
 
 
Правки
 
 
  Rev. Язык Кто Когда Δ Комментарий
en16 Английский Xellos 2015-11-29 20:49:38 16 Tiny change: 'sing maps in $O(N ' -> 'sing maps + Fenwick trees in $O(N '
en15 Английский Xellos 2015-11-27 23:14:50 6 Tiny change: 'that $L_1(i,j) > L_1(j,k)$ in th' -> 'that $L_1(j,k) > L_1(i,k)$ in th'
en14 Английский Xellos 2015-11-25 18:20:31 2 Tiny change: 'ms in $O(k)$, but th' -> 'ms in $O(k^2)$, but th'
en13 Английский Xellos 2015-11-25 01:42:21 129
en12 Английский Xellos 2015-11-25 01:12:03 5769 and done
en11 Английский Xellos 2015-11-24 23:47:45 3357 Tiny change: 'akes $O(m^2n^2)$ time' -
en10 Английский Xellos 2015-11-24 23:25:07 1864 Tiny change: 'using STL map<>/set<> data stru' -> 'using STL `map<>`/`set<>` data stru'
en9 Английский Xellos 2015-11-24 23:08:43 3981 Tiny change: 'ps in $O(N\log{N})$ time.\n' -> 'ps in $O(N \log N)$ time.\n'
en8 Английский Xellos 2015-11-24 23:01:15 305 Tiny change: '------\n\n\nIt's e' -
en7 Английский Xellos 2015-11-24 22:48:48 3940
en6 Английский Xellos 2015-11-24 22:23:59 507
en5 Английский Xellos 2015-11-24 22:07:30 1272 Tiny change: 'Hints:\n\n' -
en4 Английский Xellos 2015-11-24 21:37:47 3 Tiny change: 'm Codechef :D.\n\ndiv1E' -
en3 Английский Xellos 2015-11-24 21:37:12 877
en2 Английский Xellos 2015-11-24 20:39:12 2 (published)
en1 Английский Xellos 2015-11-24 16:26:52 109 Initial revision (saved to drafts)