### Benjamin007's blog

By Benjamin007, history, 7 weeks ago, Well, the simple answer is yes. Let me simplify it for you at first.. How can you print from 1 to n without using a loop?

By repeating this line 1000 times, Your program works just as efficiently as if you made an iterative loop from 1 to 1000.

 cout << x++ << endl;
if(x==n)return 0;


For example, this code can print you numbers from 1 to 10.. You can develop it up to 1000

    int n,x=1;
cin >> n; n++;
cout << x++ << endl; // 1
if(x==n)return 0;
cout << x++ << endl; // 2
if(x==n)return 0;
cout << x++ << endl; // 3
if(x==n)return 0;
cout << x++ << endl; // 4
if(x==n)return 0;
cout << x++ << endl; // 5
if(x==n)return 0;
cout << x++ << endl; // 6
if(x==n)return 0;
cout << x++ << endl; // 7
if(x==n)return 0;
cout << x++ << endl; // 8
if(x==n)return 0;
cout << x++ << endl; // 9
if(x==n)return 0;
cout << x++ << endl; // 10
if(x==n)return 0;


Input : 6 Output : 1 2 3 4 5 6

Well here comes the big question.. How do we print an array in reverse without using a loop? Well simply by reading the variables in ascending order and printing them in descending

Here is a small example on 5 variables:

        int n; cin >> n; //Number of Elements (Size of the array)
int x1; cin >> x1;
if (n == 1) goto line1;
int x2; cin >> x2;
if (n == 2) goto line2;
int x3; cin >> x3;
if (n == 3) goto line3;
int x4; cin >> x4;
if (n == 4) goto line4;
int x5; cin >> x5;
if (n == 5) goto line5;

line5: cout << x5 << ' ';
line4: cout << x4 << ' ';
line3: cout << x3 << ' ';
line2: cout << x2 << ' ';
line1: cout << x1 << ' ';


Input: 1 4 6 10 17 Output: 17 10 6 4 1

You can do the same thing up to 1000 elements or more..believe it or not, I solved some problems related to Arrays/Loops in this way.. And It Worked (Accepted✅) loop, Comments (14)
 » sorry, but actually I think the real expected answer was recursion, you can read the value, call the next recursion first, and then output the variable. Same logic as preorder/inorder/postorder.
•  » » 7 weeks ago, # ^ | ← Rev. 2 →   ­
 » Why not recursion? long long recur(long long n){ cout << n << "\n"; if(n <= 1) return 0; return recur(n-1); } int main(){ long long n; cin >> n; recur(n); return 0; } I don't really know if this is a scam blog or not but I answered it anyway.
•  » » This is not reversing array, you're just printing the numbers in reverse, +You'll need an array, I made it without an array
•  » » » Firstly, your solution ARE "printing the numbers in reverse", which is the same as mine.Secondly, my solution do not require any array.Finally, please consider your words precisely before commenting.
•  » » » » Ok
 » I really don't know why everyone is down-voting me.. I see it as a creative idea.. I really solved a problem with it asking me to reverse and array (and I solved it without an array/loop), and another problem asking me about printing numbers from 1 to n (and I solved it without a loop)
•  » » It is not a creative idea: What if n = 1e18? Would you love to copy-and-paste 1e18 times?
•  » » » lol if n = 1e18 you cannot store them in a array nor print them , it will take 1e9 seconds(~32 years)
•  » » 7 weeks ago, # ^ | ← Rev. 17 →   it is not creative and usable , since you can just reverse(array.begin() , array.end()); idk why would someone do that in a contest or a interview
•  » » » At least you can learn something from me is that you can take advantage of programming to write another code with repetitive lines like this  for (int i = 0; i < 10; i++) { cout << "cout << x++ << endl;\n"; cout << "if (x == n)return 0;\n"; } 
•  » » » » dont get me wrong but these are really common features , everyone uses them , maybe you should check other people's code before writing something like this idk
•  » » » » » Can you give me an example please?
•  » » » » » » like for example , we use for loop to do repetative tasks ` for(int i = 0;i