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By SP_22, history, 12 months ago, In English

I was attempting the E problem of round #878 Div 3. I am getting TLE in my code but it seems to me that the Time complexity of the code if O(T * (t + q)) which should get accepted. Please tell me the mistake in the code.

Approach: I am storing the position which are unblocked at time (relative to current time) in a queue. The string a and b are just a copy of s1 and s2 which will be blocked and unblocked throughout the process (s1 and s2 are not altered).

Problem: Div 3 E
My submission: Submission

Code
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12 months ago, # |
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Auto comment: topic has been updated by SP_22 (previous revision, new revision, compare).

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12 months ago, # |
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(string)a==(string)b isn't $$$O(1)$$$, it's $$$O(\min(|a|,|b|))$$$

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    12 months ago, # ^ |
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    So what should be done instead of that?

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      12 months ago, # ^ |
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      For example managing the positions $$$x$$$ which $$$S_{1,x} \neq S_{2,x}$$$ and $$$x$$$ isn't locked, with some data structure or smarter way.

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    12 months ago, # ^ |
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    But in my AC submission, I also did (s1 == s2) and didn't get TLE. Why so?

    Also how to check if two strings are equal in O(1)?