include<stdio.h>
int main()
{
double x=-1.99999999999999980000; while(x>-2.0&&x-1==-3.0) puts("orz"); return 0;
}
can anybody give some explaination ,thank you..
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int main()
{
double x=-1.99999999999999980000; while(x>-2.0&&x-1==-3.0) puts("orz"); return 0;
}
can anybody give some explaination ,thank you..
Название |
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I think you misunderstood me: what I mean is for x=-1.99999999999999980000 I want to know the truth of this statement:x>-2.0&&x-1==-3.0 if x==-1.99999999999999980000 how can x-1==-3.0,it should be -2.99999999999999980000 if it has accuracy error and rounding off to -3.00, but why x=-1.99999999999999980000 not rounding to -2.0 but x>-2.0.
My own machine regard this statement false,but CF compilors regard it as true,I don't why...
aha , sorry for my misunderstanding , i don't know why this happens but i think misof articles about integer and real representation can help you .
you can find it here .
https://gcc.gnu.org/bugs/#nonbugs_general