Hi, please provide an algorithm for this question: Click
I am trying it from long time but couldn't reach a proper algo.
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Время на сервере: 27.04.2024 05:29:22 (k3).
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The number of possible paths is 2*(n*(n-1)+2), so you can solve it by brute force
Can you explain how you got this number?
Okay I got it, just confirming:
For each vertex in one row there are N-1 vertices that end the Hamiltonian path.
Plus for vertex 1 and N there are N ways so that 2.
As there are 2 rows so finally multiplied by 2.
yes, i got this number in that way too