Can we apply extend Extended Euclidean algorithm for negative numbers?
Like for 3*x-4*y=1 output will be x=3 , y=2 .
Can we apply extend Extended Euclidean algorithm for negative numbers?
Like for 3*x-4*y=1 output will be x=3 , y=2 .
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3690 |
2 | jiangly | 3647 |
3 | Benq | 3581 |
4 | orzdevinwang | 3570 |
5 | Geothermal | 3569 |
5 | cnnfls_csy | 3569 |
7 | Radewoosh | 3509 |
8 | ecnerwala | 3486 |
9 | jqdai0815 | 3474 |
10 | gyh20 | 3447 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | maomao90 | 173 |
2 | awoo | 164 |
3 | adamant | 163 |
4 | TheScrasse | 160 |
5 | nor | 157 |
6 | maroonrk | 156 |
7 | -is-this-fft- | 152 |
8 | Petr | 146 |
8 | orz | 146 |
10 | pajenegod | 145 |
Название |
---|
Why don't you just try it out?
Btw, even if it doesn't work, you can solve 3*x + 4*y = 1, receive the answer (x, y) to this modified problem, and the answer to your original problem will be (x, -y).
ok got it!, Thanks.