### Nuruhuhuhu's blog

By Nuruhuhuhu, history, 21 month(s) ago, ,

I have code of finding the perpendicular distance from a point to a 3D plane. But in this case, the plane is infinite. If the plane is not infinite, but limited to a certain piece, such as the face of an object, then how to find the minimum distance from a point to that face?

An example:

If the 3 points defining a "piece" of plane are:

1 0 0

0 1 0

0 0 0

And the query point is:

1 1 1

Then the answer will be .

Is there any implementation in C++ for this problem? If yes, then could someone please provide it? And if not, then sharing the idea of solving it will also help. Thanks in advance.

• +3

 » 21 month(s) ago, # |   +15 Let h be the distance from query point Q to the plane Π that contains the face. Project Q onto Π, then find the distance d from this projection to the face (this becomes a 2D problem). Your answer is then .And when I say "this becomes a 2D problem" I mean actually make 2D points: if you have two perpendicular unit vectors v and w in Π then you can find the 2D coordinates of some point P by computing (P·v, P·w).For the code you would need something like this (details to come in my book once I've written that part): struct p3 {double x,y,z;} // assume operators +,-,etc. already defined double operator|(p3 a, p3 b) {/* dot product */} // inspired from notation p3 operator*(p3 a, p3 b) {/* cross product */} p3 unit(p3 a) {/* make unit vector from a */} struct plane { p3 o, dx, dy, dz; // plane that contains o and extends in directions dx and dy // Use any three non-collinear points to create the plane plane(p3 a, p3 b, p3 c) : o(a), dx(unit(b-a)), dz(unit(dx*(c-a))), dy(dz*dx) {} double dist(p3 a) {return abs((a-o)|dz);} pt pos2d(p3 a) {return {(a-o)|dx, (a-o)|dy};} // where pt is a 2D point type }; Use dist for h and then use pos2d on all the points (including Q) to make the problem 2D and compute d.
•  » » 21 month(s) ago, # ^ |   -8 Did you stop working on your geometry book?
•  » » » 21 month(s) ago, # ^ |   0 No, I'm still working on it, it's just taking much more time than I anticipated (especially all the darn figures). I made some progress lately, and I will post an update in a few days. :)