I tried many test cases ,I am passing all of them But it is failing at test case 5 on codeforces. Since test case are quite large ,I am unable to figure out my error.Please forgive me if my question is not good. 55748387(My submission)
I tried many test cases ,I am passing all of them But it is failing at test case 5 on codeforces. Since test case are quite large ,I am unable to figure out my error.Please forgive me if my question is not good. 55748387(My submission)
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Change removelazy(node1, l, r) to removelazy(node1, start, end1)
Still getting wrong ,should i check also if the node is lazy or not while answering the query? Because i am not checking
You need to use removelazy in your query function
I added the removelazy in query part
I think there are many other issues in the implementation. I suggest you to check your implementation once again.
https://codeforces.com/contest/52/submission/54744859 take a look at my submission
Please can you tell me where I am doing the mistake?
First of all you are consider 0 base indexing in your build() function so your left child is (node1 << 1) + 1 and right child is (node1 << 1) + 2 and your query() function is
node query(int node1, int l, int r, int start, int end1) {
}
You do not consider if(tree[node1].lazy != 0) case in your query function