chandanagrawal23's blog

Techgig Code Gladiator 2020
By chandanagrawal23, history, 4 years ago, In English

Techgig Code Gladiators 2020

Hello coders ... Techgig Code gladiators is back.

Code Gladiators is an annual coding competition by TechGig, that draws the best and the brightest coding talent from all over the world. With multiple contests in emerging technologies and the coveted title of Code Gladiators up for grabs, the competition sees enthusiastic participation and has grown from strength to strength with each passing year.

Last year I and some of my friends and very good coders from the cp community went to finals ...it was an awesome experience.

The contest has 3 Rounds -

Round 1: — 23 March 2020 to 11 May 2020 ( consist 2 coding questions )

Round 2: 14 May 2020 to 26 May 2020 (Techgig select top performers basis on no. of participation)

Round 3: Final Face-Off — 23 June 2020 [ onsite ]

And in this event, its not just for programmers in this event some amazing theme-based competition also there like RPA, Cloud, Fintech, IoT and many more.

So don't wait Register Here

-- Prizes in the Coding Competition

Winner : 3,00,000/- ₹

Ist runner up : 2,50,000/- ₹

IInd runner up : 1,75,000/- ₹

IIIrd runner up : 1,25,000/- ₹

IVth runner up : 1,00,000/- ₹

Best Female Coder : 50,000/- ₹

-- Prizes in the Theme-Based Competition

Winner : 1,50,000/- ₹

Ist runner up : 1,25,000/- ₹

IInd runner up : 75,000/- ₹

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Comments Comments (15)
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4 years ago, # |
  Vote: I like it -22 Vote: I do not like it

If anyone has any query then I will solve.

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4 years ago, # |
← Rev. 2   Vote: I like it +38 Vote: I do not like it

As per my experience, Code Gladiator need to seriously work on it's problem quality and platform :)

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    4 years ago, # ^ |
      Vote: I like it 0 Vote: I do not like it

    yes ... but I think final round problems are quite well ....last year even 7 star does not solve all problems If u r interested then register bro.

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4 years ago, # |
  Vote: I like it +10 Vote: I do not like it

With the contest over, anybody got solutions to any problems?

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    4 years ago, # ^ |
    ← Rev. 2   Vote: I like it +5 Vote: I do not like it

    I have for the distribution one (D1, D2, D3) and the mirror one.

    Distribution one: coeff. of $$$x^F$$$ in

    $$$ F!*((e^x - e^{-x})/2)^{D1}*((e^x + e^{-x})/2)^{D2}*(e^x)^{D3}$$$

    Mirror one: generate the path of the laser from the center and from the target position, the intersection points are the possible answers.

    I did not solve the mirror one though, cuz it was a straightforward, boring, and heavy implementation question (or I am just a loser making excuses).

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4 years ago, # |
  Vote: I like it 0 Vote: I do not like it

I can't see the t-shirts winners division anymore on their website. So will they not be giving the tshirts ?? Any update on this ?

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