You can use this: Use min({a,b,c}) instead of min(a,min(b,c)).
C++ is evolving ,are you?
You can use this: Use min({a,b,c}) instead of min(a,min(b,c)).
C++ is evolving ,are you?
| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | tourist | 3690 |
| 2 | jiangly | 3647 |
| 3 | Benq | 3581 |
| 4 | orzdevinwang | 3570 |
| 5 | Geothermal | 3569 |
| 5 | cnnfls_csy | 3569 |
| 7 | Radewoosh | 3509 |
| 8 | ecnerwala | 3486 |
| 9 | jqdai0815 | 3474 |
| 10 | gyh20 | 3447 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | maomao90 | 173 |
| 2 | awoo | 164 |
| 3 | adamant | 163 |
| 4 | TheScrasse | 159 |
| 5 | nor | 157 |
| 6 | maroonrk | 156 |
| 7 | -is-this-fft- | 152 |
| 8 | Petr | 146 |
| 8 | orz | 146 |
| 10 | pajenegod | 145 |
that feature has existed since C++11, so around 10 years ago
Then why does it give error on my compiler? I'm using gcc 4.3.0
I think GCC 4 is too old
At least here it says std::max with initializer list being a parameter has existed since C++11
Does adding
-std=c++0xoption to the compiler command line make it work? That's an older name of the C++11 draft before it got finalized. Ancient compilers may accept it.We know.