Разбор Codeforces Round #325

Revision ru1, by Edvard, 2015-10-12 12:03:52

Div2 problem A 12A - Super Agent

Div2 problem B 12A - Super Agent

Div2 problem C / Div1 problem A 12A - Super Agent

Div2 problem D / Div1 problem B 12A - Super Agent

Div2 problem E / Div1 problem C 12A - Super Agent

Div2 problem F / Div1 problem D 12A - Super Agent

Div2 problem G / Div1 problem E 12A - Super Agent

Div2 problem H / Div1 problem F 12A - Super Agent

Tags cf-325, editorial

History

 
 
 
 
Revisions
 
 
  Rev. Lang. By When Δ Comment
en12 English Edvard 2015-10-15 19:26:24 6 Tiny change: 'he value $2^{cnt_d}-1$ from $B$' -> 'he value $\mu (2^{cnt_d}-1)$ from $B$'
en11 English Edvard 2015-10-14 00:31:12 105
ru17 Russian Edvard 2015-10-14 00:27:58 285
ru16 Russian Edvard 2015-10-13 18:44:39 1 Мелкая правка: 'b = b' - a$ и $b - c' -> 'b = b' - a'$ и $b - c'
en10 English Edvard 2015-10-13 18:44:22 1 Tiny change: 'b = b' - a$ и $b - c' -> 'b = b' - a'$ и $b - c'
en9 English Edvard 2015-10-12 23:51:36 10516 Tiny change: 'n2 \rceil}$} \log ({3' - (published)
en8 English Edvard 2015-10-12 23:16:47 6
en7 English Edvard 2015-10-12 23:06:27 4 Tiny change: 'answer is sum by al' -> 'answer is the sum by al'
en6 English Edvard 2015-10-12 22:56:38 12 (saved to drafts)
ru15 Russian Edvard 2015-10-12 22:54:57 10 (опубликовано)
en5 English Edvard 2015-10-12 22:52:14 258
en4 English Edvard 2015-10-12 22:48:02 1 Tiny change: 'able by $2). Next we' -> 'able by $2$). Next we'
en3 English Edvard 2015-10-12 22:34:17 125
en2 English Edvard 2015-10-12 22:29:23 3616 (saved to drafts)
ru14 Russian Edvard 2015-10-12 22:26:03 2 Мелкая правка: 'мма всех $d_i$. Наибо' -> 'мма всех $B_i$. Наибо'
ru13 Russian Edvard 2015-10-12 22:16:59 9 Мелкая правка: 'значение $2^cnt_d-1$. Таким о' -> 'значение $\mu(d) (2^cnt_d-1)$. Таким о'
ru12 Russian Edvard 2015-10-12 21:45:28 18 Мелкая правка: 'намику $z_i_v_{b_1}_{b_2}_b$ в которо' -> 'намику $z_{i, v, b_1, b_2, b}$ в которо' (опубликовано)
en1 English Edvard 2015-10-12 21:44:30 9316 Initial revision for English translation (saved to drafts)
ru11 Russian Edvard 2015-10-12 18:38:48 18 Мелкая правка: ', b_2$ $z_b_v_{v_1}_{v_2}_1$.\n\nАсим' -> ', b_2$ $z_{b, v, v_1, v_2, 1}$.\n\nАсим'
ru10 Russian Edvard 2015-10-12 15:33:23 6
ru9 Russian Edvard 2015-10-12 15:32:40 12
ru8 Russian Edvard 2015-10-12 14:49:09 0 (опубликовано)
ru7 Russian Edvard 2015-10-12 14:48:56 2 Мелкая правка: 'n2 \rceil}) logC$, где $lo' -> 'n2 \rceil} logC)$, где $lo'
ru6 Russian Edvard 2015-10-12 14:48:28 326
ru5 Russian Edvard 2015-10-12 14:46:40 716
ru4 Russian Edvard 2015-10-12 14:45:00 130
ru3 Russian Edvard 2015-10-12 14:24:26 104
ru2 Russian Edvard 2015-10-12 14:17:30 9857
ru1 Russian Edvard 2015-10-12 12:03:52 414 Первая редакция (сохранено в черновиках)