Need help with UVA — 10218 — Let's Dance

Правка en1, от Bekh, 2019-02-12 20:46:16

Hello,

Here's the problem link: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1159

I know and already got AC with other, but I was trying various dp states/approaches for practice. I wanted to know what I am missing in this dp approach since I'm getting a bit lower value than the sample output (0.5012511 instead of 0.5002286)

Solution link: https://ideone.com/AjdoVF

approach: * i is zero based * Dp definition: * dp[i][rem] is probability to get a final even 'usedCandy' count in range [i, m) using 'rem' candies such that usedCandy = totalCandies — rem * base case: * at i == m, return isEven(usedCandy) * transition: * at each [i][rem], if 'tk' is amount given to man 'i'. 'tk' is in [0, rem] * answer = Summation for all 'tk' in [0, rem] -> P(man 'i' getting exactly tk candies) * dp[i + 1][rem — tk] * P(a man getting exactly 'tk' candies) having 'rem' candies in total can be found through binomial theorom C[rem][tk] * p^tk * q^(rem — tk) such that p is probability for * a person to get a single candy = 1/(m+w) and q = 1 — p

If something is not clear with my solution, please ask. Where am I going wrong with this dp?

История

 
 
 
 
Правки
 
 
  Rev. Язык Кто Когда Δ Комментарий
en5 Английский Bekh 2019-02-12 20:54:52 17 Tiny change: 'with other, but I wa' -> 'with other neater solutions, but I wa'
en4 Английский Bekh 2019-02-12 20:48:25 9
en3 Английский Bekh 2019-02-12 20:47:36 2 Tiny change: 'proach: \n * i is ' -> 'proach: \n\n * i is '
en2 Английский Bekh 2019-02-12 20:47:19 26
en1 Английский Bekh 2019-02-12 20:46:16 1279 Initial revision (published)