According to Wikipedia, an RMQ can be built with $$$O(n)$$$ memory ($$$O(n)$$$ precomp) that can answer queries in O(1).
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Enumerating all Binary Trees to build O(n)/O(1) RMQ
Revision en5, by SecondThread, 2019-11-24 20:49:19
History
Revisions
| Rev. | Lang. | By | When | Δ | Comment | |
|---|---|---|---|---|---|---|
| en9 |
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SecondThread | 2019-11-24 21:14:02 | 0 | (published) | |
| en8 |
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SecondThread | 2019-11-24 21:13:06 | 18 | Tiny change: 'lockSize^2)$.\n\nBut' -> 'lockSize^2 * nCartesianTrees)$.\n\nBut' | |
| en7 |
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SecondThread | 2019-11-24 21:11:49 | 149 | ||
| en6 |
|
SecondThread | 2019-11-24 21:08:55 | 1011 | ||
| en5 |
|
SecondThread | 2019-11-24 20:49:19 | 8 | ||
| en4 |
|
SecondThread | 2019-11-24 20:47:34 | 2 | Tiny change: 'ilt with _O(n)_ memory (' -> 'ilt with __O(n)__ memory (' | |
| en3 |
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SecondThread | 2019-11-24 20:47:26 | 4 | Tiny change: 'uilt with `O(n)` memory (O' -> 'uilt with _O(n)_ memory (O' | |
| en2 |
|
SecondThread | 2019-11-24 20:45:24 | 3 | Tiny change: 'uilt with O(n) memory (O' -> 'uilt with `O(n)` memory (O' | |
| en1 |
|
SecondThread | 2019-11-24 20:44:50 | 161 | Initial revision (saved to drafts) |
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