| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | tourist | 3757 |
| 2 | jiangly | 3647 |
| 3 | Benq | 3581 |
| 4 | orzdevinwang | 3570 |
| 5 | Geothermal | 3569 |
| 5 | cnnfls_csy | 3569 |
| 7 | Radewoosh | 3509 |
| 8 | ecnerwala | 3486 |
| 9 | jqdai0815 | 3474 |
| 10 | gyh20 | 3447 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | maomao90 | 171 |
| 2 | adamant | 164 |
| 3 | awoo | 163 |
| 4 | TheScrasse | 159 |
| 5 | nor | 155 |
| 6 | maroonrk | 154 |
| 7 | -is-this-fft- | 152 |
| 8 | Petr | 147 |
| 9 | orz | 146 |
| 10 | pajenegod | 145 |
Count of rectangles that can be formed with stream of points
This question was asked in an online screening test. Any clue how to solve it with Online Approach better than O(N^3)?
My Approach:
Maintain two maps of Map<X, Set> and Map<Y, Set> and for each point find horizontal and vertical points and for every triplet check 4th point exist or not.
