bugdone's blog

By bugdone, history, 2 months ago,

Today in 1557C - Moamen and XOR I wanted to compute ${(2^{k-1})}^{n}$. But instead of writing binpow(binpow(2, k — 1), n), I simplified it to $2^{(k-1)*n}$ and wrote binpow(2, mul(k — 1, n)) and failed to pass pretest 2.

Why are not the two equivalent?