Given the m ranges that denotes subarray of an array of length n i --> [l ,r] 1<=l<=r<=n Cost of Concatination of two ranges is 1 Find the min cost to overlap the whole array or return -1 if not exist
1<=n<=100
Plz help. Thanks in advance
# | User | Rating |
---|---|---|
1 | ecnerwala | 3648 |
2 | Benq | 3580 |
3 | orzdevinwang | 3570 |
4 | cnnfls_csy | 3569 |
5 | Geothermal | 3568 |
6 | tourist | 3565 |
7 | maroonrk | 3530 |
8 | Radewoosh | 3520 |
9 | Um_nik | 3481 |
10 | jiangly | 3467 |
# | User | Contrib. |
---|---|---|
1 | maomao90 | 174 |
2 | adamant | 164 |
2 | awoo | 164 |
4 | TheScrasse | 160 |
5 | nor | 159 |
6 | maroonrk | 156 |
7 | -is-this-fft- | 150 |
8 | SecondThread | 147 |
9 | orz | 146 |
10 | pajenegod | 145 |
Given the m ranges that denotes subarray of an array of length n i --> [l ,r] 1<=l<=r<=n Cost of Concatination of two ranges is 1 Find the min cost to overlap the whole array or return -1 if not exist
1<=n<=100
Plz help. Thanks in advance
Name |
---|
If I understood correctly, you can concatenate two overlapping ranges: concat([1, 4], [3, 6]) = [1,6]. Then I have this solution:
Complexity is O(n^2); can be reduced to O(n*log n) if you sort the ranges.
Got it thanks