By DeadlyCritic, history, 15 months ago,

In the name of God;

Hi, here I want to suggest some random functions for Testlib.

Testlib has nice random functions, here I want to suggest some other ones. The first and the second random functions are available in testlib, but the rest are not.

1, $\text{rnd.next(l, r)}$, it will return a random number in range $l$ to $r$ with equal weights :

2, $\text{rnd.wnext(l, r, w)}$, it will return a random number in range $l$ to $r$ with monotonically increasing/decreasing weights depending on $w$ :

If $w = 0$ then it will be equal to $\text{rnd.next(l, r)}$.

If $w > 0$ :

If $w < 0$ :

3, $\text{rnd.cnext(l, r, c)}$, it will return a random number in range $l$ to $r$ :

If $c = 0$ then it will be equal to $\text{rnd.next(l, r)}$

If $c > 0$ :

If $c < 0$ :

4, $\text{rnd.cnext(l, r, c1, c2)}$, it will return a random number in range $l$ to $r$ like $\text{rnd.cnext(l, r, c)}$, but its not centered around $\frac {r+l} 2$ : ($c1 \ge 0$ and $c2 \ge 0$)

About the implementation of $\text{cnext(l, r, c1, c2)}$, its as follow :

1. Choose $c1+c2+1$ random numbers in rage $l$ to $r$ and sort them.

2. Return $c1+1$-th one.

As you can see if $c1 = c2$ then its equal to $\text{cnext(l, r, c1)}$.

If $c1 = 0$ then it will be equal to $\text{wnext(l, r, -c2)}$, if $c2 = 0$ then it will be equal to $\text{wnext(l, r, c1)}$.

Please share your suggestions in the comment section.

• +27

 » 15 months ago, # | ← Rev. 3 →   +8 $\text{cnext(l, r, c)}$ for negative $c$ will be like this : Return $\text{wnext(l, r, 2 ⋅ c + 1)}$ or $\text{wnext(l, r, -(2 ⋅ c + 1))}$ with equal probability.
 » 15 months ago, # | ← Rev. 2 →   0 MikeMirzayanov Please add $\text{cnext}$. Also one can define $\text{cnext(l, r, c1, c2)}$ for negative $c1$ and $c2$, but I didn't add it here.
 » 15 months ago, # | ← Rev. 2 →   0 As you can see for an integer $x$ in range $l$ to $r$, the weight of it for different random functions is as follow :1, $\text{wnext(l, r, w)}$ : $\begin{cases} 1, & \text{if$w = 0$} \\ (x-l+1)^w - (x-1)^w, & \text{if$w > 0$} \\ (r-x+1)^{-w} - (r-x)^{-w}, & \text{if$w < 0$} \end{cases}$2, $\text{cnext(l, r, c)}$ : $\begin{cases} \text{same as next(l, r)}, & \text{if$c = 0$} \\ (x-l+1)^c \cdot (r-x+1)^c, & \text{if$c > 0$} \\ (x-l+1)^{-2 \cdot c + 1} - (x-l)^{-2 \cdot c + 1} + (r-x+1)^{-2 \cdot c + 1} - (r-x)^{-2 \cdot c + 1}, & \text{if$c < 0$} \end{cases}$3, $\text{cnext(l, r, c1, c2)}$ $\begin{cases} \text{same as cnext(l, r, c1)}, & \text{if$c1 = c2$} \\ \text{same as wnext(l, r, c1)}, & \text{if$c2 = 0$} \\ \text{same as wnext(l, r, -c2)}, & \text{if$c1 = 0$} \\ (x-l+1)^{c1} \cdot (r-c+1)^{c2}, & \text{if$c1 > 0$and$c2 > 0$} \end{cases}$
•  » » 15 months ago, # ^ |   0 I don't know how it can be useful for a random person, but no matter what, its beautiful.