MikeMirzayanov's blog

By MikeMirzayanov, 10 years ago, translation, In English

The round will start on 08:00 (UTC) of April, 13. It will be a kind of unusual round because at first for a long time Gerald didn't work much on round. It was prepared by me (how it is interesting to write a round!), Nerevar with the help of Gerald and Fefer_Ivan-а. Maria, many thanks for translations!

It will be classical points: 500 — 1000 — 1500 — 2000 — 2500.

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By MikeMirzayanov, 10 years ago, translation, In English

Hi!

I think everybody can remember a case when

Probably everyone remembers in practice a case when after implementation of correct algorithm you receive Wrong Answer. In such a situation, sometimes works: to send solution on another compiler.

Gerald and Nerevar have found severe bug, which gives one more argument to use the rule above.

Look closely, now it will be a miracle! 

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Tags bug, g++
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By MikeMirzayanov, 10 years ago, translation, In English

Some months ago we've found that YuukaKazami took part in contests using one more account. We've contacted him and he pleaded guilty and deplored about it. That acccount has been banned and YuukaKazami was disallowed to take part in rounds for two months.

Now he can take part and we hope to see him again in standings.

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By MikeMirzayanov, 10 years ago, translation, In English

About two days ago Java 8 has been released! It is a great update with many interesting improvements and features. If you do not plan to use new language syntax, probably Java 8 will please you with performance improvements.

I've added Java 8 with options like for other versions of Java: java.exe -Xmx512M -Xss64M -DONLINE_JUDGE=true -Duser.language=en -Duser.region=US -Duser.variant=US -jar %s.

Right now, Java 8 supported in testing mode. Let's try it together on problemset problems.

You may see new features in this code — it sorts lines in non-increasing lexicographical order:

import java.util.*;

public class Main {
    public static void main(String[] args) {
        try (Scanner scanner = new Scanner(System.in)) {
            List<String> lines = new ArrayList<>();
            while (scanner.hasNextLine()) {
                lines.add(scanner.nextLine());
            }
            lines.stream().sorted((a, b) -> b.compareTo(a)).forEach(System.out::println);
        }
    }
}

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By MikeMirzayanov, 10 years ago, translation, In English

On 02.03.14 there was a serious technical failure: Codeforces and related infrastructure hard drives have been corrupted. Unfortunately, it turned out that in contrast to all other components, the Codeforces database was not replicated properly. Polygon and Gym files were not injured. However, the Codeforces data has been significantly damaged.

We've rolled back the system to the state on February 7. It will remove 22 days of Codeforces life. Immediate efforts will be directed at the total exclusion of such situations. This is a very serious loss for me personally, which I can only blame myself.

Many thanks for all of you who supported us on a temporary Codeforces page. You helped much to find motivation in this difficult situation.

Currently the Gym is disabled. It will be opened back soon. We will return official contests and gym trainings with problems (but not results).

Data to be recovered:

  • official contests with problems (but without results);
  • public trainings in Gym;
  • non-public trainings in Gym, but we do not know their owners — write me if you've prepared non-public training in Gym (not a mashup).

Sorry again for the inconvenience.

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By MikeMirzayanov, 10 years ago, translation, In English

The contest Testing Round 9 is a special contest to test recent Codeforces internal improvements. Please, take part in it to help us to be ready for Codeforces Round 224 (Div. 2).

The Testing Round 9 will be completely unofficial and unrated. We will use problems from some Saratov contests, they will be new for many of you.

If you see any issues in Codeforces behaviour, write a comment here.

Thank you!

UPD. The contest completed. Thanks to all the participants.

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Announcement of Testing Round 9
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By MikeMirzayanov, 10 years ago, translation, In English

Hurry! Only until the 10th of January, you can change your handle! Note that it will be possible to roll back the changes or change the handle again only after a year.

Talking about handles I always reminisce the following story. Once a user wrote me the message: "Please change my handle from I_love_Valya to I_love_Sveta, as I no longer love Valya ..."

Happy New Year!

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By MikeMirzayanov, 10 years ago, translation, In English

Hello! Do you feel the breath of New Year?

The clock shows a day before New Year, so it is time to sum up the past. I do not have speech-writers for words in the style of "what recently seemed almost impossible, it becomes a fact of life" so I'll be short. Thank you all! Your unfading interest and constant help inspire Codeforces team for new achievements! Brilliant writers, invisible soldiers: testers, tireless and greedy for knowledge participants — all of you help Codeforces do better!

I've dug into the records and made a partial list of the most notable major improvements of 2013. Some large improvements of our infrastructure are not in the list, as the community can not see them directly.

  • A simple way to add contest from Polygon to Codeforces::Gym.
  • Drafts embedded in text form fields in Codeforces and Polygon.
  • Multiple interface improvements in the contest area.
  • Many improvements of Testlib.
  • Notably improved performance of Polygon on large manual tests.
  • Repeatedly updated compiler versions to the nearly latest.
  • Supported languages: MS C#, Python 3, Go, JavaScript V8.
  • Updated Codeforces testing servers.
  • Polygon supported HTTPS.
  • Organized the first season of weekly Codeforces trainings 12 episodes.
  • Supported organizations in the profile and rating of organizations.
  • Added numerous contests to Codeforces::Gym. Probably the most valuable — a large number of Andrew Stankevich Сontests.
  • Implemented checker and validator tests in Polygon.
  • Implemented macro language support in test scripts in Polygon.
  • Groups on Codeforces have appeared, they can contain contests and blogs.
  • Introduced Mashup Contests — special contests for personal and group training, can be easily composed by problems from rounds or from Polygon.

In addition, in 2013 we not only hosted 64 classical Codeforces rounds, but hosted some tournaments:

Also we took a role of ACM-ICPC 2013 World Finals Press Partner!

And as the detective story can not be without a chase, and the annual report can be do without the fun pictures. Here is a series of images showing the growth of Codeforces:

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By MikeMirzayanov, 10 years ago, translation, In English

I've found some time to support JavaScript, which is so popular now. I chose V8 as the most developed implementation of JavaScript.

With the help of a tambourine and a liter of cola I successfully compiled it on Windows. Funny, I was ready to implement workaround to support reading from stdin in JavaScript, but d8 already supports it! Just use readline() to read line from the input.

Here is an example of A+B:

var line = readline().split(' ')
print(parseInt(line[0]) + parseInt(line[1]))

Interesting fact, that if there is no line-break (\r\n) at the end of line, then readline() returns undefined. So it is one more reason for good rule: each line should end with eoln.

As a tiny research I've implemented HeapSort on C++, Java and JavaScript. I have an opinion that all dynamic typed languages are very slow. But...

I've implemented HeapSort on 107 elements from 0 to 9999999. I think it is good benchmark to show how fast can be your code if you write like in Pascal or pure C. The result have surprised me:

Language Compiler Running time, ms
C++ MinGW 4.7.2 32-bit 630
C++ MS VS 2010 32-bit 650
Java Oracle Java 6 32-bit 1060
Java Oracle Java 7 32-bit 1050
JavaScript V8 3.23.0 32-bit 1700
Pascal Delphi 7 32-bit 630
Pascal FreePascal 2.6.2 32-bit 730
Python 2 Python 2.7.4 32-bit 12500
Python 3 Python 3.3.2 32-bit 20000
Ruby Ruby 1.9.3p0 (2011-10-30, i386-mingw32) 32-bit 520000
Ruby Ruby 2.0.0p353 (2013-11-22, i386-mingw32) 32-bit 345000
Scala Scala 2.10.3 (over Oracle Java 7 32-bit) 1550
Go Go 1.2 32-bit 1780
D DMD v2.064.2 32-bit 800
C# Mono 2.10.9 32-bit 850
C# MS CSC .Net 4.5.1 64-bit 850
Perl Perl v5.12.2 for MSWin32-x86-multi-thread 195000

JavaScript shows very good performance! I understand that such kind of code is very good for optimization and jit-compilation, but I'm impressed. By the way, Java with its optimized JIT is not as good as it can be.

Actually, I posted the codes in github. You may implement the same algorithm on your favorite language. Here are links to current implementations:

You may post links to pastebin in comments or give submission id. Better to do a pull request.

If you are planning to write implementation, please write it neat and tidy. Write it as closer to the C++, Java and JavaScript as possible.

UPD 1. With the help of alexei-zayakin, Pascal has been added.

UPD 2. With the help of gchebanov Wizmann and juancate I've added Python 2, Python 3, Ruby, Scala, Go.

UPD 3. Here is V8 (Windows binaries).

UPD 4. I've updated some compilers and the benchmark results.

UPD 5. Added D. Thanks Gassa.

UPD 6. Added C#. Thanks gmogelashvili.

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By MikeMirzayanov, 10 years ago, translation, In English

The tutorial has been prepared by Fefer_Ivan and NALP.

371A - K-Periodic Array

For array to be periodic, elements 1, 1 + k, 1 + 2 * k, … must be equal. Also, elements 2, 2 + k, 2 + 2 * k, … must be equal. And so on up to k. So each element of the array is a part of exactly one group. And there are k groups total. Each such group is independent. Let’s consider some group of elements, that contain a ones and b twos. All elements in this group must be equal. So we either change all ones to twos or all twos to ones. First option will require a changing operations and second one — b changing operations. For the optimal solution, you should select the operation with smaller number of changing operations required.

371B - Fox Dividing Cheese

It is easy to see that the fox can do three type of operations: divide by 2, divide by 3 and divide by 5. Let’s write both given numbers in form a = x·2a2·3a3·5a5, b = y·2b2·3b3·5b5, where x and y are not dibisible by 2, 3 and 5. If x ≠ y the fox can’t make numbers equal and program should print -1. If x = y then soluion exists. The answer equals to |a2 - b2| + |a3 - b3| + |a5 - b5|, because |a2 - b2| is the minimal number of operations to have 2 in the same power in both numbers, |a3 - b3| is the minimal number of operations to have 3 in the same power in both numbers, and |a5 - b5| is the same for 5.

371C - Hamburgers

Let's use binary search approach. For given number of hamburgers (say, x) let's find the minimal number of money needed to cook them. Say, for one hamburger Polycarpus needs cb bread pieces, cs sausages pieces, cc cheese pieces. So for x hamburgers he needs: cb·x, cs·x and cc·x pieces (by types). Since he already has nb, ns and nc pieces, so he needs to buy:

  • bread: max(0, cb·x - nb),
  • sausages: max(0, cs·x - ns),
  • cheese: max(0, cc·x - nc).

So the formula to calculate money to cook x hamburgers is:

f(x) = max(0, cb·x - nbpb + max(0, cs·x - nsps + max(0, cc·x - ncpc

Obviously, the function f(x) is monotonic (increasing). So it is possible to use binary search approach to find largest x such that f(x) ler.

371D - Vessels

The naive solution for this problem will work like this. Let us store an amount of water in each vessel in some array v. If we need to know how much water is in some vessel, we just take the number from the array. If we need to pour x units of water into vessel number i, we must follow the simple procedure: 1. If x = 0 then all water is poured and we must end the procedure 2. If i > n then all remaining water is spilled on the floor and we must end the procedure 3. If x units of water can fit into the i-th vessel, then add x to v[i] and end the procedure 4. Fill i-th vessel completely and subtract used amount from x. 5. Assign i = i + 1. 6. Go to the first step.

In the worst case scenario such procedure can iterate through all vessels each time. For example, if there are n vessels and each vessels have capacity of one unit of water, each query like 11n will take O(n) time to process.

To make this solution faster we should notice, that once completely filled, vessel can be skipped during the algorithm above because it can not consume any more water.

So instead of i = i + 1 assignment should be like i = findNextNotFilledVessel(i).

To implement this function we can use different structures. For example, we can use sorted set of numbers (set in C++, TreeSet in Java). Let store the set of indices of unfilled vessels. So to find next not filled vessel from i-th vessel, we must find smallest number, that is contained in set and is strictly greater than i. There are built-in methods for it (upper_bound in C++, higher in Java).

Also, each time we fill the vessel, we must erase corresponding index from the set.

So now we can see, that algorithm can not complete more that O((m + n)logn) operations for all queries. Because on each iteration of the pouring procedure either the vessel is filled (which can only happen n times during the whole runtime), or we run out of water (or vessels) and the procedure is stopped. So there will be only total of O(m + n) iterations of the pouring procedure and each iteration require one lookup in the sorted set, which takes O(logn) operations. So the total number of needed operations is O((m + n)logn).

371E - Subway Innovation

It is easy to see that you need to minimize the sum of pairwise distances between k stations. The main idea to do it is to sort them and the required stations will form a continuous segment. It is easy to prove by contradiction.

Huge constraints do not allow to use straight-forward method to find required segment. Let’s call f(i, k) — sum of pairwise distances of k stations starting from the i-th. To find f(0, k) you need to start from f(0, 0) = 0 and use transformation from calculated f(0, i) to f(0, i + 1). You can use equation:

 = f(0, i) + xi·i - sum(0, i - 1)

where sum(l, r) means xl + xl + 1 + ... + xr. We can precalculate sum[i] = x0 + x1 + ... + xi and use equation sum(l, r) = sum[r] - sum[l - 1] to find sum(l, r) in O(1).

Actually we need f(0, k), f(1, k) and so on (and find minimal value among them).

To recalculate f(i, k) to f(i + 1, k) you need exclude xi and include xi + k. Using the method like in the previous paragraph: f(i + 1, k) = f(i, k) - (sum(i + 1, i + k - 1) - xi·(k - 1)) + (xi + k·(k - 1) - sum(i + 1, i + k - 1)).

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By MikeMirzayanov, 10 years ago, translation, In English

Please take a notice that recently the schedule has been changed. Twice.

Greetings to the Codeforces community!

I'm glad to announce that we again decided to introduce a round based on one of the programming olympiads for schoolchildren in Saratov. This time it is a round for participants from Division II. Round will start at unusual time for Codeforces: Dec. 7, 07:00 UTC.

The problems were prepared by employees and students of Programming Competitions Training Center of Saratov State U.

Members of the first division can participate out of competition, as usual.

Currently we are planning to use dynamic scoring system.

UPD: Moved from 09:00 to 07:00 because of Kotlin Challenge.

UPD 2: Tutorial has been published.

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By MikeMirzayanov, 10 years ago, translation, In English

Tomorrow (December, 1st) at 06:00 (UTC) Northeastern European Regional Contest 2013 will start. Use the link to view the current stangings during the contest.

The contest will take place in four cities at the same time: Saint-Peterburg, Barnaul, Tbilisi, Tashkent. Looking to the standings of the practice session it is clear that totally 235 teams will fight for the honour to take part in the Finals.

NEERC takes place since 1996. Here are NEERC Champions:

Year Winner
1996 Spb ITMO
1997 Spb SU
1998 Moscow SU
1999 Spb SU
2000 Spb SU
2001 Spb ITMO
2002 Moscow SU
2003 Spb ITMO
2004 Spb ITMO
2005 Moscow SU
2006 Moscow SU
2007 Spb ITMO
2008 Saratov SU
2009 Petrozavodsk SU
2010 Spb ITMO
2011 Spb ITMO
2012 Spb ITMO
2013 Spb SU

I wish all the teams to show their strongest sides. Good luck!

P.S. For sure, I will be rooting for Saratov State University. You know well our leading team: Gerald, Fefer_Ivan, kuviman.

P.S. The contest finished. My congratulations to:

  • The 1st place: SPb SU 4 (Kunyavskiy, Egorov, Suvorov)
  • The 2nd place: Moscow SU 1 (Pyaderkin, Evstropov, Omelyanenko)
  • The 3rd place: Saratov SU 1 (Agapov, Fefer, Kudasov)

The complete standings are here.

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By MikeMirzayanov, 10 years ago, translation, In English

Welcome to 2013-2014 CT S01E012: Codeforces Trainings Season 1 Episode 12. The training duration is 5 hours. It is opened for teams as well as for individual participants. After the end you may use the practice mode to complete problem solving. Also it will be availible as a virtual contest for whose of you who can't take part today. Please, do not cheat. Only fair play!

It is possible that the problems will be too easy for some participants, it is possible that we will add some problems.

The registration will be available on the Gym page and will be opened until the end of the training. Be careful registering team: please, choose only whose members who will take part in the contest.

Please do not take part in the contest if you have already solved the contest problems before.

Good luck!

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By MikeMirzayanov, 10 years ago, translation, In English

Welcome to 2013-2014 CT S01E011: 2013-2014 ACM-ICPC East Central North America Regional Contest (ECNA 2013). The training duration is 5 hours. It is opened for teams as well as for individual participants. After the end you may use the practice mode to complete problem solving. Also it will be availible as a virtual contest for whose of you who can't take part today. Please, do not cheat. Only fair play!

It is possible that the problems will be too easy for some participants, it is possible that we will add some problems.

The registration will be available on the Gym page and will be opened until the end of the training. Be careful registering team: please, choose only whose members who will take part in the contest.

Please do not take part in the contest if you have already solved the contest problems before.

Good luck!

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By MikeMirzayanov, 10 years ago, translation, In English

Hello,

I know that the news will upset some of you: the round was moved 1.5 hours forward and it will start on 17:00 UTC.

As for me — the reason is very pleasant. The round original time coincided with a sniper's accuracy with the celebration of my daughter's birthday. Oh, St. Dijkstra, Tatyana is 2 years old! Last week I did many changes in judging backend (around caching) and I don't want in case of some issues to have a choice — to have a bad round or to have a bad celebration. I hope you understand!

Also I'm sure that new time will be more comfortable for some of you.

Hope to see you on the round!

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By MikeMirzayanov, 10 years ago, translation, In English

Welcome to 2013-2014 CT S01E09: 2011 German Collegiate Programming Contest (GCPC 2011) + GCJ 2009 R3 C-D. The training duration is 5 hours. It is opened for teams as well as for individual participants. After the end you may use the practice mode to complete problem solving. Also it will be availible as a virtual contest for whose of you who can't take part today. Please, do not cheat. Only fair play!

It is possible that the problems will be too easy for some participants, it is possible that we will add some problems.

The registration will be available on the Gym page and will be opened until the end of the training. Be careful registering team: please, choose only whose members who will take part in the contest.

Good luck!








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By MikeMirzayanov, 11 years ago, translation, In English

Welcome to 2013-2014 CT S01E08: 2013 ACM-ICPC Rocky Mountain Regional Contest (RMRC 2013) + GCJ 2009 WF C-D. The training duration is 5 hours. It is opened for teams as well as for individual participants. After the end you may use the practice mode to complete problem solving. Also it will be availible as a virtual contest for whose of you who can't take part today. Please, do not cheat. Only fair play!

It is possible that the problems will be too easy for some participants, it is possible that we will add some problems.

The registration will be available on the Gym page and will be opened until the end of the training. Be careful registering team: please, choose only whose members who will take part in the contest.

Good luck!

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By MikeMirzayanov, 11 years ago, translation, In English

Hello,

Did you already notice that this Sunday it will be Internet-version of 2013-2014 ACM-ICPC, NEERC, Southern Subregional Contest? It will start on 07:00 (UTC).

The contest will be held in Gym. I invite teams mostly because the contest was designed as a team contest.

I'm sure this contest is a great way to train before coming regional (or subregional for some of you) ACM-ICPC contest.

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By MikeMirzayanov, 11 years ago, translation, In English

Welcome to 2013-2014 CT S01E07: Codeforces Trainings Season 1 Episode 7. The training duration is 5 hours. It is opened for teams as well as for individual participants. After the end you may use the practice mode to complete problem solving. Also it will be availible as a virtual contest for whose of you who can't take part today. Please, do not cheat. Only fair play!

It is possible that the problems will be too easy for some participants, it is possible that we will add some problems.

The registration will be available on the Gym page and will be opened until the end of the training. Be careful registering team: please, choose only whose members who will take part in the contest.

Good luck!

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By MikeMirzayanov, 11 years ago, translation, In English

Welcome to 2013-2014 CT S01E06: 2002-2003 ACM-ICPC Northwestern European Regional Contest (NWERC 2002) + Some Problems from COCI and POI. The training duration is 5 hours. It is opened for teams as well as for individual participants. After the end you may use the practice mode to complete problem solving. Also it will be availible as a virtual contest for whose of you who can't take part today. Please, do not cheat. Only fair play!

It is possible that the problems will be too easy for some participants, it is possible that we will add some problems.

The registration will be available on the Gym page and will be opened until the end of the training. Be careful registering team: please, choose only whose members who will take part in the contest.

Good luck!

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By MikeMirzayanov, 11 years ago, translation, In English

Welcome to 2013-2014 CT S01E05: 2007 Nordic Collegiate Programming Contest (NCPC 2007) + Selected Problems from 2009 Google Code Jam World Finals (GCJ WF 2009). The training duration is 5 hours. It is opened for teams as well as for individual participants. After the end you may use the practice mode to complete problem solving. Also it will be availible as a virtual contest for whose of you who can't take part today. Please, do not cheat. Only fair play!

It is possible that the problems will be too easy for some participants, it is possible that we will add some problems.

The registration will be available on the Gym page and will be opened until the end of the training. Be careful registering team: please, choose only whose members who will take part in the contest.

Good luck!

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