How internally upper_bound for sorted vector(in ascending order) works in c++. Let say 'A' is a sorted vector.Then how upper_bound(A.begin(),A.end(),x) will directly give iterator to first element greater than x. Thanks in advance.
How internally upper_bound for sorted vector(in ascending order) works in c++. Let say 'A' is a sorted vector.Then how upper_bound(A.begin(),A.end(),x) will directly give iterator to first element greater than x. Thanks in advance.
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Auto comment: topic has been updated by hellomoto (previous revision, new revision, compare).
The functional behavior of the
std::upper_bound()template is described in www.cplusplus.com.It is basically based on binary search. Therefore, its time-complexity should be
, provided that random-access of any item is done in constant-time that is independent of problem size 
which is the count of items between the first and the last item.
thanks.
With pleasure.