guys I was using double in my code but unexpectedly it's printed "nan" in output!!! can anyone tell me where did it originated form??
double y;
cout<<1-y; __ wrong output format Expected double, but "nan" found
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There is special value of
double
called NaN (Not-a-number). It may be caused by disallowed operations i.e sqrt(-1).In your case, it's probably due to division by zero (d) in
y=p<n-1?0:u/d;
. Weird...