Tommyr7's blog

By Tommyr7, history, 2 weeks ago, In English,

Hi, Codeforces!

I'm quite excited to invite you to Codeforces Round #439 (Div. 2) which takes place at 16:35 MSK on 6 October and lasts for two hours.

One of the five problems is created by quailty, and the others are created by me. This is our first round here.

The round couldn't have been realized without efforts of KAN and gritukan. Besides, I also want to say thanks to our testers: cyand1317, visitWorld, Nisiyama_Suzune, cdkrot and gainullin.ildar. Thanks for your help to the contest. Also, thanks to MikeMirzayanov with the fantastic Codeforces and Polygon platforms.

The contest will consist of five problems and it is rated for Div. 2 contestants. The same as before, Div. 1 contestants can take part out of competition.

The problems will feature... Well, let's wait and see for another time ;) As per Codeforces tradition, moderate length text and no spoilers about the actual plot.

I hope you can have fun during the contest. Good luck and have fun, wish you high rating!

The scoring distribution will be announced later.

See you tomorrow!

UPD1 : The scoring distribution is 500-1000-1500-2250-2500.

UPD2 : The contest is over. The editorial is available.

UPD3 : Congratulations to top five coders!

Division 2 :

  1. 1heart2plans (solved all problems!)
  2. fatice
  3. LuckyPants
  4. xza
  5. T404

Division 1 + Division 2 :

  1. 1heart2plans (solved all problems!)
  2. unused
  3. fatice
  4. nuip
  5. chemthan

Have fun! See you next time! (Let's wait and see...)

 
 
 
 
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2 weeks ago, # |
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Auto comment: topic has been updated by Tommyr7 (previous revision, new revision, compare).

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    13 days ago, # ^ |
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    The E's data has some weak,because many people violence passed,but if Op 1 is 50000 and op 3 is 50000 many people will be TLE.

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      13 days ago, # ^ |
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      Well... It's my issue... In fact, the generator for div2. E isn't easy to code... I added 20 tests after randomly getting the ractangles... and I didn't consider this situation... Maybe I will do better next time... Thanks for pointing out!

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2 weeks ago, # |
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Tommyr7's round, must be very nice to perticipate.

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Another chinese round. Hope for short problem statements.

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Not only Chinese round,but Shanghai Round as well.It must be a fantastic one as the ones written by cyand1317!

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2 weeks ago, # |
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WOW Shanghai Round OvO

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2 weeks ago, # |
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zici!

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2 weeks ago, # |
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%%%%Q神

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2 weeks ago, # |
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Wow, another round with special starting time. I can't stop craving those thought-provoking problems.

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2 weeks ago, # |
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Very good! Hope the statement will be short.

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2 weeks ago, # |
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Hy guyzzzz , is it RATEDD??

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2 weeks ago, # |
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Auto comment: topic has been updated by Tommyr7 (previous revision, new revision, compare).

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2 weeks ago, # |
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I did terribly today and cannot wait until tomorrow to try to restore my confidence.

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2 weeks ago, # |
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gl hf every one

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2 weeks ago, # |
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Everybody who wrote the contest bad. I wish they can do that better next time

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2 weeks ago, # |
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Hope this contest problems also have a short statements like previous. Wish everybody luck! YA!

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2 weeks ago, # |
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guyzzz , plig reply , is the contest rated ?

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    2 weeks ago, # ^ |
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    If there written "Codeforces Round #***", it means that it is rated. But not always, for example.

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      13 days ago, # ^ |
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      Right. In addition, "Codeforces Round #***" can be unrated if there occurs any unexpected technical problem (though those contests are declared as rated, later they're declared as unrated in those cases).

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2 weeks ago, # |
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Wish that this contest announcement will be, as short as, statement)

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2 weeks ago, # |
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Yeah, This contest will held on my Dad's birthday.The bad thing that I will be doing this contest during my family сelebrating dad's birthday(((

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    2 weeks ago, # ^ |
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    I really think you should celebrate your dad's birthday in case contest clashes with the party time :)

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Finally came to a Chinese Round!Fantastic! Zici Tommyr7's first round. And ORZ Giant Red Q ! I think at Tommyr7's and quailty's level , it's not difficult at all to prepare for Div1!

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    2 weeks ago, # ^ |
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    Yes, and they (classified information) with (classified information).

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    2 weeks ago, # ^ |
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    Well, it's our first round. So I think it more proper to prepare for just one Div. 2 round.

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      13 days ago, # ^ |
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      proper uh... how to understand this words ? my English is not so good sorry ... proper means suit? maybe... QAQ

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2 weeks ago, # |
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Chinese Round,fighting!

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Congratulations....hope your 1st contest will be very interesting and expecting high rating :)

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So before every contest, I get an email announcement for the upcoming contest, and every time it states that the contest has an unusual start time.

Out of curiosity when is the usual start time?

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2 weeks ago, # |
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For quailty hit call(escape

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If you ask me zici not zici, I'm zici

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EMPTY

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As someone who is about to retire, I hope to have a happy ending.Come on!

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13 days ago, # |
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quailty, I hope the problem's quality is very good.

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Auto comment: topic has been updated by Tommyr7 (previous revision, new revision, compare).

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13 days ago, # |
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I wonder how Tommyr7 became rating ~2300 so fast (3-4 months) from rating 1800 (with many participation)...

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    13 days ago, # ^ |
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    In fact... I can't performance well in Div. 2 contests and I even don't know why...

    Always FST on div2AB may be one of the reasons...

    You can see that I fst problem B yesterday again... which makes me very upset...

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13 days ago, # |
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Let's Hack it!!!!

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13 days ago, # |
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Someone tell me how to solve C??

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    13 days ago, # ^ |
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    excuse me?

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    13 days ago, # ^ |
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    Let me bring my crystal ball... Oohhhh, I can't find it. Must have missed it on the field some day.

    Well, now you're gonna need to read the problem first.

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    13 days ago, # ^ |
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    You can do it greedily. Just sort the array and try all the numbers from smallest to largest.

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    13 days ago, # ^ |
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    You can use Brute force. Just O(n^2). n is less than 10000. So brute force can solve it.

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      13 days ago, # ^ |
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      But time limit is only 439 miliseconds. And implementation is pretty heavy so the program can be slow. How can you deal with it?

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        13 days ago, # ^ |
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        You can use fastIO, such as read() or fread(). :)

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      13 days ago, # ^ |
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      The brute force solution seems to be O(n^2), but is actually O(n*log(n)), so the solution can easily pass all tests.

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    13 days ago, # ^ |
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    I solved it with Convex Hull on linked list! :)

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Yay! I don't have to feed the cows this morning. Let's have fun in this contest :) !!!

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Really Pixar:)

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How to Solve problem C :D

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Today's round ID is 869, which is one of the substring of E869120. I'm lucky that I can participate.

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    13 days ago, # ^ |
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    The next contest which's ID will be in your username as substring will be 912. After some more contests :)

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the start round doesn't suit me, i've to run from college to home quickly and the contest has started 10 minutes :)

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It seems that chinese round is difficult as usual.

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    13 days ago, # ^ |
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    That's why people shouldn't vote up the announcement before they read problems.

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I am not being able to open any solution for hacks. [Locked solutions]

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Awesome Chinese names got me!! :-P Instead of "Koyomi", I wrote "Kayomi" and got pretests passed. So, I locked for hacking and now I realized that I made a mistake!! Worst feeling when you know your submission is going to fail in system testing and you cant do anything :-P

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    13 days ago, # ^ |
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    dont worry...have hope...it wont fail :p

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    13 days ago, # ^ |
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    The answer is always Karen so don't worry and you'll be accepted

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      13 days ago, # ^ |
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      Damn...that is great! Totally missed it.

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        13 days ago, # ^ |
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        I realized that when I tried to hack this code:

        int main() { printf("Karen\n"); }

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          13 days ago, # ^ |
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          It's not always :)

          Consider the case: 2 4 1 5 4

          No of pairs: 3 (1,1) (2,1) (2,2)

          Luck wasn't in my side, and contest got over before i could hack a submission.

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            13 days ago, # ^ |
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            all numbers are distinct

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              13 days ago, # ^ |
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              Oops, I missed those constrains.

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      11 days ago, # ^ |
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      Why is it always Karen? Sorry I'm kind of slow on these things.

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        11 days ago, # ^ |
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        It's easy to see, xor(X,Y) = xor(Y,X) right ? So if (X,Y) is a valid pair, (Y,X) would be as well.

        As you can see the answer comes in pairs, that's why it's always even.

        Don't forget that xor(X,X) = 0 and 0 is not allowed in the problem so you will never count this one.

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          11 days ago, # ^ |
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          Thanks, I get it now. I was suspecting it was the xor but not sure until now.

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    13 days ago, # ^ |
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    I guess the names are Japanese as the characters from the problems are a part of an anime known as the Monogatari Series.

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      13 days ago, # ^ |
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      Yes, they're Japanese names. Though Kanbaru didn't appear in problems XD

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        12 days ago, # ^ |
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        XD ? what does it mean ? it's a abbr?

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          12 days ago, # ^ |
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          Rotate it by 90° clockwise.

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            12 days ago, # ^ |
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            still can't understand it! sorry... Please forgive my ignorance

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502 Bad Gateway

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C is savage :/

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13 days ago, # |
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since when codeforces started allowing Div2 participants in Div1 contests.....???

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How to solve A ? [ What is the hack case for A as I solved it using O(n * n)]

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    13 days ago, # ^ |
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    ans for A is always "Karen".

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    13 days ago, # ^ |
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    The answer will always be karen because the number of pairs will be even always. Suppose, for pair (1,2) the answer(xor of both numbers) exists in array, then obviously for (2,1) answer will also exist. Hence for x (x1,x2) number of pairs there are other x(x2,x1) pairs. Hence 2x pairs in total. so the answer will be karen.

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13 days ago, # |
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I am not able to see other solution for hacking after locking my solution. Also my score shows 0 in my room. Why is this happening? :/

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Problem descriptions were not that long. Thank you!

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It was a high quality round.

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13 days ago, # |
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what should be the output for

1 1048576 1048575

in A ? update- it was my mistake .

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13 days ago, # |
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Math, Math and more Math.

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13 days ago, # |
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I did hashing on fenwick tree for problem E. Even though I did double hashing, I'm still crossing my fingers.

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13 days ago, # |
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When you're < 30 seconds late from submitting a solution.......

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13 days ago, # |
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Is there any alternate approach to E, mine is ->

I maintain a 2D BIT, where in every cell I store hash of set of rectangles that affected it. For query, I just check if hash of given two cells is same. Query as well as updating all elements inside rectangle while adding or deleting it takes O(log(n)2) time.

My hashing technique though is very naive, first I assign unique numbers to rectangles, now I maintain few functions like sum of numbers, sum of squares, xor of numbers, xor of squares in every cell. Comparing two cell then will require to compare these 4 numbers. Using lesser and better functions should also suffice.

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A. Nice Hello World

B. Nice problem for Python

C. Nice problem for Python

D. Nice difficulty

E. Nice data structure

The difficulty distribution is 500-500-1500-3000-2000.

Please dynamic problem scoring.

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13 days ago, # |
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Mathematic round

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13 days ago, # |
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do the pretests of E contain big tst cases

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13 days ago, # |
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In problem B one should check for 0!/0! case answer should be 1 .

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How to solve C?

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    13 days ago, # ^ |
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    Fix the number of edges between a-vertices and b-vertices. Let there be x of them. Choose x out of a possible a-nodes and x out of b possible b-nodes and connect them in x! ways. Do same for a-c and b-c pairs. Multiply all 3 values to get final answer.

    Code

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      13 days ago, # ^ |
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      I don't get it :/. What do you mean by "Fix the number of edges between a-vertices and b-vertices" ? Can you explain with the example a={1,2} and b={1,2,3} ?

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        13 days ago, # ^ |
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        x can range between 0 and min(a, b). In this case, x can be 0, 1 or 2.
        If x = 0, number of ways = C(a, 0) * C(b, 0) * 0!
        If x = 0, number of ways = C(a, 1) * C(b, 1) * 1!
        If x = 0, number of ways = C(a, 2) * C(b, 2) * 2!
        C(n, r) is number of ways of choosing r objects from n objects.

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          13 days ago, # ^ |
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          C(a, 0) * C(b, 0) * 0!,
          C(a, 1) * C(b, 1) * 1!,
          C(a, 2) * C(b, 2) * 2!

          Sir, can you explain why you multiplied the expression with the factorial? 0!, 1!, 2!??? satyaki3794

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            13 days ago, # ^ |
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            After you've chosen x values each from the two sets of nodes, you need to make x pairs from them. For the first a-node, you have x possible b-nodes to choose from. Make a pair. Now, for the 2nd a-node, you have x-1 possible b-nodes to choose from, and so on. Total ways is x!.

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              13 days ago, # ^ |
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              Thank you so much ! :) Makes perfect sense to me now!

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    13 days ago, # ^ |
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    Calculate F(a, b) independently for 3 pairs and multiply.

    if a <  = b, F(a, b) = F(a - 1, b) + F(a - 1, b - 1) * b

    Because, for 1st element of first set, if nothing is assigned in 2nd set, there are F(a - 1, b) ways left, and if 1st is assigned in b ways, F(a - 1, b - 1) ways are left.

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      13 days ago, # ^ |
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      why not so:F(a-1,b-1)*a+F(a,b-1)

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        13 days ago, # ^ |
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        The relation is symmetric, hence I mentioned a <  = b before it.

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          13 days ago, # ^ |
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          But How are they independent of each other ???

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            13 days ago, # ^ |
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            When you have joined a point in set 1, with a point in set 2, joining this point to any point in set 3 doesn't contradict any given conditions, hence you can treat them as independent.

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13 days ago, # |
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swap(D,E)

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13 days ago, # |
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I did not enjoy the difficulty this round. The difficulty was A, A, D, E, E. One small mistake on the first two problems can drop your rank by 500.

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13 days ago, # |
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I've been tricked After I hacked someone's code,I saw this: #define int long long int

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    13 days ago, # ^ |
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    That's cruel.

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    13 days ago, # ^ |
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    Exactly this was something I faced in a previous round. From then, I always check ;)

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      Yeah,I will check it from now on.I were so innocent...

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    13 days ago, # ^ |
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    I use this, It save me from overflows :D

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      13 days ago, # ^ |
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      but long long int is time consuming.

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        13 days ago, # ^ |
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        Codeforces is not so strict with time limits :D until you are writing some sub-optimal solution in which case you need to edit this #define int long long

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wanna cry, come to the solution of C in the last ten minutes but fail to submit it.

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x[i]^y[i] Test 23 A

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Answer of A is Always Karen ????

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    13 days ago, # ^ |
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    Yah

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    13 days ago, # ^ |
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    Yes. Because, if A^B = C then B^C = A and A^C = B both are true. When you find a pair A and B such that A^B = C and C is one of the numbers of your list, then it's guaranteed that you will find another pair looks like A^C (Which will give B) or B^C (Which will give A). So for one successful XOR another successful XOR is guaranteed!

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    13 days ago, # ^ |
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    ordered pairs was the key word.

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Auto comment: topic has been updated by Tommyr7 (previous revision, new revision, compare).

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13 days ago, # |
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Oh my god, I made an obvious mistake and I passed the pretest of problem A..... Farewell my rating.

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using map in A gets TLE :(

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    13 days ago, # ^ |
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    Solution was O(1) answer is always Karen :D

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    13 days ago, # ^ |
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    Same here

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    13 days ago, # ^ |
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    no it doesn't my submission

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      13 days ago, # ^ |
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      but why it's with me:31069010

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        13 days ago, # ^ |
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        It's giving TLE with [] operator but passing with find() but both are logarithmic in complexity .

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          13 days ago, # ^ |
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          Using [] operator adds keys to the map(if it doesnt exist), thus making it too large for further operations. So find() runs fine but [] gives TLE. Made the exact same mistake !

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            12 days ago, # ^ |
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            I had a small doubt, if [] is making keys then when it is called for the second time why doesn't it return true.

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              11 days ago, # ^ |
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              Map stores key value pairs. Sure it adds new keys, but maps them to false value.

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    13 days ago, # ^ |
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    Lol, never use a map just to map something to bool, you can always just use set in such case instead.

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13 days ago, # |
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O(N^2*6) DP getting TLE in C but O(N^2) Pascal's trangle passing :( too strict time limit

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13 days ago, # |
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Auto comment: topic has been updated by Tommyr7 (previous revision, new revision, compare).

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13 days ago, # |
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CodeForces runs 10^8 operations in 1 second? correct me

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13 days ago, # |
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In problem C, it is Impossible to solve the problem in Java using O(N2) Dp. However the same solution, in c++ passes like a wonder.

Remember that I used my mind to come up with an idea for a good problem, I type the Code in Java, TLE on pretest #7. The same code I type in C++, AC 740 MS. So, U should also prefer a better language, not only use ur brain to solve problems.

I have been facing disappointments like these from time to time.

I'm just going to stop using Java anymore, because I feel a lack of respect towards it in the programming Community.

Some Proof :

C++

Java

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    13 days ago, # ^ |
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    It's not impossible http://codeforces.com/contest/869/submission/31077410 , there are others, you can see it on http://codeforces.com/contest/869/status/C , just set the language to Java ... I don't think there is suck lack, look to the top ones in the rating and you gonna see that some of them use Java

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      13 days ago, # ^ |
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      It's not that it's impossible in Java, it's just that you need much lesser effort (less efficient code) using c++ and much more effort (highly optimized code ) using Java

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      13 days ago, # ^ |
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      Some problems are impossible to solve in java, especially the ones using TreeMap/TreeSet. The fact is C++ has the advantage and java is at a disadvantage.

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13 days ago, # |
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how 2 solve E in 8 minutes like fatice did ?

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    13 days ago, # ^ |
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    begin with E first read problem in 1 minute think for 2 minutes code BIT in 1 minute code others in 3 minutes submit code in 1 minute

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    12 days ago, # ^ |
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    In fact, fatice ranked 1st in CNOI2017.

    He's really cool.

    /And I was shocked when I knew he took part in the round...lol

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      12 days ago, # ^ |
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      That 's amazing !!! When I was in the game, I was shocked when I looked at the rankings. Now read his code, I think in this life I can hardly write such a simple and concise code. lol

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      11 days ago, # ^ |
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      31072413 This is fatice's solution for problem C. It is really short and clean and I think it's awesome. Any idea what dp[i][j] represents?

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13 days ago, # |
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Perfect contest time after a long week.

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13 days ago, # |
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This contest is not showing up in my profile. Is there some time to wait before it is updated?

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13 days ago, # |
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checking an element a1 in map like ma.find(a1)!=ma.end() passes all the testcases for A but checking like ma[a1]!=0 gets TLE. why??

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    13 days ago, # ^ |
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    When you use the second option, an element with key a1 is inserted on the map, so the runtime will be slower since you gonna have more values in your map

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      13 days ago, # ^ |
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      but time complexity is same for both the cases and also atmost 4*10^6 elements will be inserted.

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13 days ago, # |
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Running on tc22 for 15 mins...Can someone explain why

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13 days ago, # |
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why in problem A mp[] gives TL ,, okay it will insert more elements in the map but still the max size of the map should be 2000+2000+(2000*2000)=4004000 so the overall complexity should be n*n*log(4004000) and this should pass in one second!

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13 days ago, # |
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The constraints given in problem A are wrong thats why my solution did not pass The constraints for xi and yi given are 1 — 2*1000000 whereas actually the constraints are 1-4*1000000. Please correct me if I am wrong.

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    13 days ago, # ^ |
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    You can see my submissions for problem A. The only difference between two codes is size of array 'ha'

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    13 days ago, # ^ |
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    constrains is right but A^B may be more than 2*10^6

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13 days ago, # |
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when the ratings will be updated? can't wait to become purple

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13 days ago, # |
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Am I the only one who solved problem B by finding the repeating pattern of the last digits of b!/a! ?? This is my solution.

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13 days ago, # |
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Is there anyone else or just me who was not able to understand the test output of Problem C :P ?

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13 days ago, # |
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ratings?

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13 days ago, # |
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What kind of joke it is to provide editorial of only 2 problems? :/

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13 days ago, # |
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when the rates updated??

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13 days ago, # |
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what is difference between finding in map and direct checking? ex. map<int,int>mp; mp.find(x)!=mp.end() and mp[x]!=0

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    13 days ago, # ^ |
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    If you access a key using the indexing operator [] that is not currently a part of a map, then it automatically adds a key for you. This makes a really large map (up to 4000000) in this problem. You should use .find() or .at() for lookup.

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13 days ago, # |
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Is there a good deterministic solution to E?

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13 days ago, # |
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How to solve D?

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13 days ago, # |
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Why does my Python 2.7.12 solution get a runtime error when I use xrange (on TC 21) and pass when I use range with the same arguments. This is not supposed to happen. It works fine on my laptop but fails on Python and PyPy here. This cost me

xrange: http://codeforces.com/contest/869/submission/31091691

range: http://codeforces.com/contest/869/submission/31091663

Literally the only difference is the x[range]

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    13 days ago, # ^ |
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    If you use Python 2/PyPy 2, xrange doesn't take args from 2**31 and higher (>=2147483648) (on here that is)

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      13 days ago, # ^ |
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      Same for me.. i knew this already large arguments in xrange dont work. I checked it and 10**18 was working in my pc i got runtime error while submitting. Took time to realize.

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13 days ago, # |
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My solution is hacked again. It's a sad story.T_T

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13 days ago, # |
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Auto comment: topic has been updated by Tommyr7 (previous revision, new revision, compare).

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12 days ago, # |
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If 1e18*9 is not allowed by long long,then I could have hacked many solutions on B:D

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12 days ago, # |
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Auto comment: topic has been updated by Tommyr7 (previous revision, new revision, compare).

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11 days ago, # |
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this contest was too weeaboo for me, couldn't take it :(

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10 days ago, # |
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