By RAD, 7 years ago, translation, In English,
Today in Russia it's not just the 20th of september, it's Recruiter's Day. In Azerbaijan – Oil Industry Worker's Day, and in Belarus – Customs Officer's Day. But for us it's another good day to arrange the round. Welcome to Codeforces Beta Round #29 (Div. 2, Codeforces format)!

Helped with preparation of the round: Mike MirzayanovDmitry MatovGerald Agapov and Nickolay Kuznetsov, thank them for that.

Happy Recruiter's Day,
Artem Rakhov

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By Polichka, 7 years ago, translation, In English,

Attention-Attention!!!

Today Saratov SU #1 (Gerald, Polichka, Fefer) team invites all of you to take part in Codeforces Beta Round #28. 

We began studing sport-programming in school. But when we entered the Saratov State University we took it seriously and made our way from SU #7 to Saratov SU #1. Now our first-grade ambition is to justify this number.

We are going to offer you 5 interesting problems. You will be helping some good people to deal with their problems, will be solving some administrative tasks, will be playing some interesting games and also will be saving the World.

Thanks to everyone for their help in preparing this round. 

Successful hacks and fast accepteds!
With best regards, Saratov SU #1.

UPD: Ratings have been updated.

UPD:

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By RAD, 7 years ago, translation, In English,
We want to congratulate you with a happy new school year with this contest. We wish you excellent marks, easy exams and many Accepted in the contests. Let this year bring you many new and interesting knowledge!

Artem Rakhov and Codeforces team 

P. S. Note that the round will be held on the Codeforces Format Rules. Read the rules before the competition. Good luck!

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By Nedy88, 7 years ago, In English,
Hello everybody,

Codeforces Beta Round #26 will be held on Monday, the 16th of August, at 19:00 MSK. It will be Codeforces format round, and if all goes well it will be rated. Authors of the problems are Artem Rakhov and me. Thanks to Mike Mirzayanov and Dmitry Matov for help in organizing it. Also thanks to Julia Satushina for translation of problems.

Good luck, see you on the round!

UPD: The contest is over, thank you to everyone for participating.

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By RAD, 7 years ago, translation, In English,

Welcome to Codeforces Beta Round #25 (Div. 2)


Authors of today's round problems are Mike Mirzayanov and me. I want to thank to Dmitry Levshunov for technical assistance in organizing the contest, as well as Gerald Agapov and Nikolay Kuznetsov for writing alternative solutions.


I wish you all good luck!


UPD: The contest is over, thank you to everyone for participating.

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By Egor, 7 years ago, translation, In English,

Task A

This is pretty simple task - we have cycle and must direct all edges on it in one of 2 directions. We need to calculate cost of both orientation and print smallest of them.
There is a small trick - we can calculate cost of only one orientation and then cost of the other will be sum of costs of all edges minus cost of first orientation.

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By Nedy88, 7 years ago, In English,
Hey everybody,

Wellcome to Codeforces Beta Round #24. I'm author to most of the problems today. Something about me: My name is Nedyalko Prisadnikov and I'm a student from Sofia University in Bulgaria. Here are some pictures of me. Many thanks to Mike Myrzayanov and to Artem Rakhov for organizing the contest, writing alternative solutions and some of the problems.

Good luck and have fun!

UPD:

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Announcement of Codeforces Beta Round #24
 
 
 
 
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By RAD, 7 years ago, translation, In English,
Hi everybody

Today the author of the majority of problems is Dmitry Zhukov, many thanks to him for this. 
Also I want to thank Mike Mirzayanov for choosing problems for the contest and organizing it and Julia Satushina for the translation of the statements.

Good luck!

UPD:

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Announcement of Codeforces Beta Round #23
 
 
 
 
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By iakolzin, 7 years ago, translation, In English,

Contest discussion

Problem А. Second Order Statistics

Sorting

In this problem one should find a minimal element from all elements, that are strictly greater, then the minimal one or report that it doesn't exist. Of course, there can be a lot of different solutions, but one of the simplest - to sort the given sequence and print the first element, that's not equal to the previous. If all elements are equal, then the required element doesn't exist.

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By RAD, 7 years ago, translation, In English,

Welcome all to Codeforces Beta Round #22

Note that at this time registration is possible during the round. The contest will begin at 19:00 MSK.

Today I am an author of the problems. I would like to thank Mike Mirzayanov for help in contest preparations, Edvard Davtyan and Nickolay Kuznetsov for writing the verification solutions, and Julia Satushina for translating statements into English.

Good luck on the contest!

UPD: The contest is over. Thank you all for participating!
Problems
Results
Winner Kasparyanm_Mihail gains +203 to rating after the contest!

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